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stira [4]
3 years ago
5

The 12 girls on the dance team want to raise $300.00 to buy practice shoes. They have already raised $137.52. If each girl raise

s the same amount, how much more money must each student raise?
A. $13.54
B. $25.00
C. $11.46
D. $36.46
Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
It would be A $13.54
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Answer:0.6

Step-by-step explanation:

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Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.
aev [14]

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

  • a² - b² is a difference of two squares
  • a² - b² = (a + b)(a - b)

∵ The binomial is 81 a² - 25 z^{6}

∵ \sqrt{81} = 9

∵ \sqrt{a^{2} } = a

∴ \sqrt{81a^{2}}=9a

∵ \sqrt{25} = 5

∵ \sqrt{z^{6}} = z³

∴ \sqrt{25z^{6}}=5z^{3}

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 z^{6}  is a difference of two squares

∵ Its factorization is two identical brackets with different

   middle signs

∵ 81 a² = 9a × 9a

∵ 25 z^{6} = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 z^{6} = (9a + 5z³)(9a - 5z³)

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

#LearnwithBrainly

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3 years ago
A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A
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Answer: C

Step-by-step explanation:

<u>Given:</u>

Sample size (n) = 50

x = 12

\widehat{\mathbf{p}}=\frac{\mathbf{x}}{n}=\frac{12}{50}=0.24

Confidence level = 90%

α = 1 − 0.90 = 0.10

α/2 = 0.05

\text { Critical value }\left(z_{c}\right)=z_{\frac{\alpha}{2}}=z_{0.05}=1.6449

(from standard normal table)

90% Confidence interval is,

\begin{aligned}&\text { Confidence interval }=\widehat{\mathbf{p}} \pm z_{c} \times \sqrt{\frac{\hat{\mathbf{p}}(1-\hat{\mathbf{p}})}{n}} \\&\text { C. I }=0.24 \pm 1.6449 \times \sqrt{\frac{0.24(1-0.24)}{50}} \\&\text { C. I }=0.24 \pm 1.65 \times \sqrt{\frac{0.24(1-0.24)}{50}}\left\end{aligned}

Therefore, 90% confidence interval for the true proportion of sophomores who favour the adoption of uniforms is C

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Answer:

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Step-by-step explanation:

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