Answer:
Domain: 
Range: 
Step-by-step explanation:
The domain is the set of real values which can be inputted into a function and produce a real output. In this case, the domain is the following: , because this is the set of real values for which the function will produce a real output.
The range is the set of real values which a function outputs when a value from the domain is entered into the function. This is the set of y-values that one can see on the graph, the possible y-values are in between (-3) and (6).
Responder:
24 litros; 16 litros; 4 litros
Explicación paso a paso:
Dado que:
Gasolina consumida = 20 litros
Sea la cantidad de gasolina en el tanque = x
Primera parte del viaje = 2/3 de x
Segunda parte del viaje = 1/2 de (x - 2x / 3)
Cantidad de gasolina en el tanque:
2x / 3 + 1/2 (x - 2x / 3) = 20
Solución para x
2x / 3 + x / 2 - x / 3 = 20
(4x + 3x - 2x) / 6 = 20
5 veces / 6 = 20
5 veces = 20 * 6
5 veces = 120
x = 120/5
x = 24
Cantidad de gasolina en el tanque = 24 litros
Litros consumidos en cada etapa:
Primera parte = 2/3 de 24 = 48/3 = 16 litros
2a parte = 0.5 de (24 - 16) = 0.5 * 8 = 4 litros
Answer:
x and y
Step-by-step explanation:
39. FALSE
40. Where is the answer?
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span> = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
= (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>
