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Oliga [24]
3 years ago
9

Just like other scientists and philosophers of his time, Archimedes believed the secrets of the universe could be revealed by th

inking alone. *
True!
False!
Physics
1 answer:
Nutka1998 [239]3 years ago
4 0
True !! Yes the answer true
You might be interested in
Help with these questions please?
egoroff_w [7]

Answer:

5. dispersion

6. 49.8°

Explanation:

5. Dispersion is the name given to the phenomenon of light of different wavelengths being bent differently. A rainbow is the result of light from a point source (the sun) being spread out by wavelength (color), a nice example of dispersion.

___

6. n = 1.31 is the ratio of the sine of the angle of refraction to the sine of the angle of incidence (for light passing to a medium of n = 1). When the angle of refraction is 90°, the angle of incidence is the "critical angle." So, ...

sin(90°)/sin(critical) = 1.31

critical angle = arcsin(1/1.31) ≈ 49.8°

8 0
3 years ago
A man with a weight of 100 N is located
valentina_108 [34]

Answer:

Given,

  mass of man = 100 N = 10 kg

   height = h = 25m

   since the man does not move anything with his force, work done by him is zero

   work done on the man = gain in potential energy

   P.E=mgh

   P.E=10×9.8×25

  P.E=2.45KJ

Explanation:

so, potential energy gained by man is 2.45 KJ

5 0
2 years ago
Air with a mass flow rate of 2.3 kg/s enters a horizontal nozzle operating at steady state at 450K, 350kPa, and a velocity of 3
MissTica

Answer:

(a) A_1=0.283m^2

(b) Q=-105.5kW: From the air to the surroundings.

Explanation:

Hello,

(a) In this case, we can compute the area at the entrance by firstly computing the inlet volumetric flow:

V_1=\frac{mRT_1}{P_1M}= \frac{2.3\frac{kg}{s} *8.314\frac{kPa*m^3}{kmol* K}*450K}{350kPa*28.97\frac{kg}{kmol} } =0.849\frac{m^3}{s}

Then, with the velocity, we compute the area:

A_1=\frac{V_1}{v_1}=\frac{0.849\frac{m^3}{s} }{3\frac{m}{s} }  =0.283m^2

(b) In this case, via the following energy balance for the nozzle:

Q-W=H_2-H_1+\frac{1}{2} mV_2^2-\frac{1}{2} mV_1^2

We can easily compute the change in the enthalpy by using the given Cp and neglecting the work (no done work):

\Delta H=H_2-H_1=mCp\Delta T=2.3kg/s*1.011\frac{kJ}{kg*K}*(300K-450K)\\ \\\Delta H=-348.795kW

Finally, the heat turns out:

Q=-348.795kW+\frac{1}{2}*2.3\frac{kg}{s}*[(460\frac{m}{s})^2   -(3\frac{m}{s})^2  ]\\\\Q=-348.795kW+243329.65W*\frac{1kW}{1000W}\\ \\Q=-105.5kW

Such sign, means the heat is being transferred from the air to the surroundings.

Regards.

4 0
3 years ago
According to this graph, which statement describes how the amount of iron changes over time in the reaction
VashaNatasha [74]
The graph shows the production of Fe, from the graph that it increases rapidly and then slowly increases.<span>The answer is a! (:
</span>
5 0
3 years ago
Which of the following breakfasts is better than eating no breakfast at all?
tigry1 [53]
The answer is A because the healthiest option out of all of those selections is the fruit smoothie.
3 0
3 years ago
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