<span>A sheet of copper could cause the object to lose the most amount of heat. Copper is an essential element and a good conductor of heat. Heat can transfer from one end of a piece of copper to the other end.</span>
Answer:
The mass m is 0.332 kg or 332 gm
Explanation:
Given
The platform is rotating with angular speed , ![\omega =8.5\, \frac{rad}{sec}](https://tex.z-dn.net/?f=%5Comega%20%3D8.5%5C%2C%20%5Cfrac%7Brad%7D%7Bsec%7D)
Mass m is moving on platform in a circle with radius , ![r=0.20\, m](https://tex.z-dn.net/?f=r%3D0.20%5C%2C%20m)
Force sensor reading to which spring is attached , ![F=4.8\, N](https://tex.z-dn.net/?f=F%3D4.8%5C%2C%20N)
Now for the mass m to move in circle the required centripetal force is given by ![F=m\omega ^{2}r](https://tex.z-dn.net/?f=F%3Dm%5Comega%20%5E%7B2%7Dr)
=>![4.8=m\times 8.5 ^{2}\times 0.20](https://tex.z-dn.net/?f=4.8%3Dm%5Ctimes%208.5%20%5E%7B2%7D%5Ctimes%200.20)
![=>m=0.332\, kg](https://tex.z-dn.net/?f=%3D%3Em%3D0.332%5C%2C%20kg)
Thus the mass m is 0.332 kg or 332 gm
When an object absorbs an amount of energy equal to Q, its temperature raises by
![\Delta T](https://tex.z-dn.net/?f=%5CDelta%20T)
following the formula
![Q=m C_s \Delta T](https://tex.z-dn.net/?f=Q%3Dm%20C_s%20%5CDelta%20T)
where m is the mass of the object and
![C_s](https://tex.z-dn.net/?f=C_s%20)
is the specific heat capacity of the material.
In our problem, we have
![Q=2.44 \cdot 10^3 J](https://tex.z-dn.net/?f=Q%3D2.44%20%5Ccdot%2010%5E3%20J)
,
![m=235.0 g](https://tex.z-dn.net/?f=m%3D235.0%20g)
and
![\Delta T=35 K](https://tex.z-dn.net/?f=%5CDelta%20T%3D35%20K)
, so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal: