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2 years ago

8

PLEASE HELP

1 answer:

Oksi-84 [34.3K]2 years ago

3 0

The answer is D) s/cos55°

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What is the solution of the system?

mario62 [17]

Y + 7 = 3x.....y = 3x - 7

6x - 2y = 12
6x - 2(3x - 7) = 12
6x - 6x + 14 = 12
14 = 12 (incorrect)

when ur variables cancel out and u r left with an incorrect statement, this means there is no solution because ur lines are parallel

so ur answer is : no solution

5 0

3 years ago

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8.<br> Find the arc length of a central angle of 7pi/3 in a circle whose radius is<br> 3inches

pashok25 [27]

$\textit{arc's length}\\\\ s = r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ \theta =\frac{7\pi }{3}\\ r=3 \end{cases}\implies s=(3)(\frac{7\pi }{3})\implies s=7\pi \implies s\approx 21.99~in$

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1 year ago

How do you figure out the reciprocal of a numer? E.g 5, 2/7 and 1&2/5 ??

eimsori [14]

You need to multiply 1 and 5 plus 2.
and for 5 2/7 it would be 5 times 7 plus 2.

So...
5 2/7= 37/7

1 2/5= 7/5

6 0

3 years ago

Use the following steps to prove that log b(xy)- log bx+ log by.

borishaifa [10]

Answer with Step-by-step explanation:

a. $x=b^p$

$y=b^q$

Taking both sides log

$log x=plog b$

Using identity: $logx^y=ylogx$

$p=\frac{logx}{log b}=log_b x$

Using identity: $log_x y=\frac{log y}{log x}$

$log y=qlog b$

$q=\frac{log y}{log b}=log_b y$

b. $xy=b^pb^q$

We know that

$x^a\cdot x^b=x^{a+b}$

Using identity

$xy=b^{p+q}$

c. $log_b(xy)=log_b(b^{p+q})$

$log_b(xy)=(p+q)log_b b$

Substitute the values then we get

$log_b(xy)=(log_b x+log_b y)$

By using $log_b b=1$

Hence, $log_b(xy)=log_b x+log_b y$

3 0

2 years ago

A car is traveling at a rate of

LUCKY_DIMON [66]

50 meters per second

3600 seconds per hour

1000 meters per km

50/1000 = 0.05

1/3600 = .0002777

0.05/0.0002777 = 180km per hour

180*4 = 720km in 4 hours

8 0

3 years ago

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