Answer:
<h2>This triangle is a right triangle:</h2><h2>36² + 15² = 39².</h2>
Step-by-step explanation:
If a ≤ b <c is the length of the sides of a right triangle, then:
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
We have
![a=15\ in,\ b=36\ in,\ c=39\ in](https://tex.z-dn.net/?f=a%3D15%5C%20in%2C%5C%20b%3D36%5C%20in%2C%5C%20c%3D39%5C%20in)
Check the equality:
![L_s=15^2+36^2=225+1296=1521](https://tex.z-dn.net/?f=L_s%3D15%5E2%2B36%5E2%3D225%2B1296%3D1521)
![R_s=39^2=1521](https://tex.z-dn.net/?f=R_s%3D39%5E2%3D1521)
![L_s=R_s](https://tex.z-dn.net/?f=L_s%3DR_s)
It's a right triangle.
Answer:
The answer is D
Step-by-step explanation:
You use base times height
1/2bh
=1/2(2x+5)(4x)
Answer:
64
Step-by-step explanation:
Yes,
y=x+3
if x=0,
y=0+3
y=3
therefore (0,3) is a solution