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2 years ago

Joelle ordered 12 dozen doughnuts for the honor roll

Mathematics

1 answer:

Serjik [45]2 years ago

7 0

Answer:

The answer is there are 30 glazed donuts

Step-by-step explanation:

there are 12 donuts to a dozen therefore 12 * 12 = 144 donuts all together.

donuts with chocolate icing

$144 \times \frac{3}{8} = 54$

with white icing and sprinkles

$144 \times \frac{1}{4} = 36$

donuts with pink icing

$144 \times \frac{1}{6} = 24$

Total donuts minus donuts with icing equal glazed donuts

$144 - 54 - 36 - 24 = 30$

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Find the least squares regression equation using the school year (in number of years after 2000) for the input variable and the

Ad libitum [116K]

Answer-

The least squares regression equation using the school year (in number of years after 2000) for the input variable and the average cost (in thousands of dollars) for the output variable is "y=0.937x+12.765" .

Solution-

The independent variable / input variable= x = Number of years after 2000 ( = year-2000)

The dependent variable / output variable = y = Average cost in thousands of dollars

(The table has been attached herewith.)

To find the regression equation for a group of (x,y) points,

We have to calculate the slope and y-intercept, then we can put those values in the equation y = mx + c ( Slope - Intercept formula)

We know that,

$Slope=m=\frac{N\sum xy -\sum x\sum y}{N\sum x^{2}- (\sum x)^{2}}$

Putting the values from the table,

$m=\frac{(8 \times 1020.206)-(52 \times 150.894)}{(8 \times 3810)-(52^2)}$

( ∵ Instead of 150,894 we have to put 150.894 as we have find the line for year and thousands of dollars )

$\Rightarrow m =\frac{8161.648-7846.488}{3040-2704} =\frac{315.16}{336}=0.937$

Now, for the y-intercept,

$c =\frac{\sum y -m(\sum x)}{N}$

Putting the values,

$c=\frac{150.894-(52 \times 0.937)}{8}=\frac{102.125}{8}=12.765$

Now, putting the values of c and m, in the Slope-Intercept formula,

$y=0.937x+12.765$

3 0

3 years ago

a student has answered 82% of the questions correctly in the examination. He made mistakes in 9 questions Calculate the toltal n

Sonja [21]

Answer:

There is a total 50 questions.

Step-by-step explanation:

Let x = total questions in the exam

Since 82% of the test was scored correctly, that means 18% of the student's exam was scored incorrectly.

With this information we can write:

$18\%x=9$ (Given that the student made 9 mistakes)

$x=9\div18\%$ (divide 18% on both sides)

$x=50$

∴ There was a total of 50 questions in the examination.

5 0

3 years ago

A manufacturing company produces parts that are good (90%), partially defective (2%), or completely defective (8%). These parts

Schach [20]

Answer:

The probability that a part is good given that it passed the inspection machine is P=0.978.

Step-by-step explanation:

As the inspection machine detect and discard any part that is completely defective, only the good and partially defective parts passed this inspection.

Then, if we have:

Probability of being a good part P(G)=0.90

Probability of being a patially defective part P(P)=0.02

Probability of being a completely defective part P(D)=0.08.

Probability of passing the inspection machine = 1-P(D)=1-0.08=0.92

Then, the probability of having a good part, given that it passed the inspection machine is:

$P(G|Pass)=P(G)/P(Pass)=0.90/0.92=0.978$

4 0

3 years ago

There are 5 4/5 cups of milk left in a carton . Write 5 4/5 as an improper fraction

Ludmilka [50]

You multiply 5 x5 =4 =29/5

5 0

3 years ago

Read 2 more answers

An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact

SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y = 2 $*$ x³ $*$ y,

18xy = 2 $*$ 3 $*$ 3 $*$ x $*$ y,

− 10x²y = 2 $*$ - 5 $*$ x² $*$ y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 $*$ - 5 $*$ 3 $*$ 3 $*$ y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

$2y\left(x^3+9x-5x^2-45\right)$ - Factor out " $(x^3+9x-5x^2-45\right))$ " by grouping,

$\left(x^3-5x^2\right)+\left(9x-45\right)$ - Factor 9 from 9x - 45 and x² from x³ - 5x²,

$9\left(x-5\right)+x^2\left(x-5\right)$ - Factor out common term x - 5,

$\left(x-5\right)\left(x^2+9\right)$ - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0

3 years ago