Answer:
Θ
Θ
Θ =
Explanation:
Applying the law of conservation of momentum, we have:
Δ
Θ (Equation 1)
Δ
Θ (Equation 2)
From Equation 1:
Θ
From Equation 2:
sinΘ =
Replacing Equation 3 in Equation 4:
Θ (Equation 5)
And we found Θ from the Equation 5:
tanΘ=
Θ=
The correct answer would be 1.7 m/s:
Start with what you know. In the y-direction, we know the jumper must fall 15 meters and starts with 0 velocity in the y direction. You can also assume that the acceleration of gravity is pulling down on the jumper at 9.8 m/s. Once you have these three you can plug it into kinematic a equation to find time
x=Vot+1/2at^2
15=(0)t+1/2(9.8)(t)^2
t=1.75
You get time=1.75 seconds. Since this is a kinematics problem, both the x and y direction have the same amount of time. You can then see that the x displacement is 3 to avoid the rocks, and acceleration is 0 in the x direction because no force is speeding it up. Therefore you can use the same equation to find initial velocity and final velocity, which are gonna be the same because we have 0 acceleration:
X=Vot+1/2at^2
3=Vi(1.75)+1/2(0)(1.75)^
Vi=1.7
1.7 is your answer
I have my work in the picture I really like to make charts to help keep everything organized if that helps you
Answer:
The balanced condition for Wheatstones bridge is
Q
P
=
S
R
as is obvious from the given values.
No, current flows through galvanometer is zero.
Now, P and R are in series, so
Resistance,R
1
=P+R
=10+15=25Ω
Similarly, Q and S are in series, so
Resistance R
2
=R+S
=20+30=50Ω
Net resistance of the network as R
1
and R
2
are in parallel
i=
R
V
=
50
6×3
=0.36 A.
Explanation:
Answer:
Power = 79.38 W
Explanation:
Given Data:
Mass of the snake head = m = 180 g = 0.18 kg
Velocity of snake = v = 21 m/s
Time = t = 0.5 sec
Required:
Average Power = P = ?
Solution
Power = work done / time
Work done = W = change in Kinetic Energy =
Since Vi = zero as snake was at rest at initial stage, thus
Work done =
Substituting this value in power equation
Answer : Celestial or azimuth - altitude
Explanation :
Celestial : The celestial coordinates that are analogous to longitude and latitude are called RA and Dec.
RA = Right Ascension
Dec = Declination
RA is the measured in unit of time and Dec is measured in degree.
The equatorial coordinate system is the projection of the latitude and longitude coordinate system on the celestial sphere.
Azimuth - altitude : Azimuth - altitude define the location of an object in the sky.
The altitude is the distance of an object appears to be above the horizon.
The Azimuth of the object is the angular distance along the horizon to the location of the object.