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nika2105 [10]
4 years ago
14

What evidence supports the ages of our planets, moon, sun, and asteroids

Physics
1 answer:
Pie4 years ago
6 0

It is indeed true that scientists have known about the background radiation (commonly known as the Cosmic Microwave Background) since the early 60s. It was first discovered quite by accident by Penzias and Wilson working at Bell Labs, who detected it as an unexplainable interference in their precision radio equipment. When people finally figured out exactly what it was they were seeing, they won the Nobel Prize for their discovery. Only a few years before, George Gamow had predicted that if the Big Bang theory were correct, we should observe just such a background radiation. The CMB is not the only evidence in favor of the Big Bang, but it is one of the most important. It is a natural consequence of the theory, and is pretty unexplainable in steady-state cosmology.

The 15-20 billion year number comes not from the CMB, but rather predominantly from measurements of nearby and distant galaxies, particularly their rates of expansion away from us. We find that the distance to a galaxy is proportional to its recessional velocity. The constant of proportionality is the Hubble Constant, H, which turns out to be (approximately) the reciprocal of the age of the universe. So we measure the age by measuring recessional velocities. T = 1/H is only true, however, if the universe is not significantly accelerating or decelerating its expansion rate. If the rate of expansion is rapidly accelerating, the universe may be older than 1/H = 15 billion years, give or take. Such an acceleration would be caused by a large value of the Cosmological Constant, a sort of anti-gravity force predicted by General Relativity. There is some evidence that this might be the case.

So finally, yes, the age of the universe, being based on the empirical determination of H, is based on the observed evidence.

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A 4.0 kilogram train going right at 6.0 meters per second bumps into a toy wagon moving the same direction at 2.0 meters per sec
aliya0001 [1]

Answer: 1.5kg

Explanation:

5 0
3 years ago
A person drops a ball off the top of a 10 story building. What statement below best describes the movement of the ball?
irina [24]

Most helpful Answer~

There are no options~

Anyway If the ball is of bad quality it will get deflated/ or strike out.

' The must reasonable thing that could happen is that the ball will bounce'

*Smile* :)  

3 0
3 years ago
A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.
Len [333]

Explanation:

Given

Velocity v = 23.0m/s

Distance S = 3.45m

Required

Time it will take the skier to reach the ground;

Using the equation of motion;

S = ut + 1/2gt²

3.45 = 23t + 1/2(9.8)t²

3.45 = 23t + 4.9t²

4.9t²+23t-3.45 = 0

Factorize;

t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)

t = -23 ±√529+67.62/9.8

t = -23±√596.62/9.8

t = -23±24.43/9.8

t = 1.43/9.8

t = 0.146 secs

Hence take the skier 0.146 secs to reach the ground.

b) Horizontal distance covered is the range;

Range = U√2H/g

Range = 23√2(3.45)/9.8

Range = 23√6.9/9.8

Range = 23√0.7041

Range = 23(0.8391)

Range = 19.29m

Hence the horizontal distance travelled in air is 19.29m

7 0
3 years ago
Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800c. Mavis and Stanley start timers at zero when t
yawa3891 [41]

Answer:

a) x=2*10^{9} m and t=8.35 s

b) t = γt', so it is 8.35 s.

Explanation:

a) The equation of Lorentz transformations is given by:

x=\gamma(x'+ut')  

x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.

  • x' = 0
  • t' = 5.00 s
  • u =0.800 c, c is the speed of light 3*10⁸ m/s

\gamma=\frac{1}{\sqrt{1-(u/c)^{2}}}

\gamma=\frac{1}{\sqrt{1-(0.800c/c)^{2}}}

\gamma=\frac{1}{\sqrt{1-(0.800)^{2}}}

\gamma=1.67

x=1.67(0+0.800c*5.00)

x=2*10^{9} m

Now, to find t we apply the same analysis:

t=\gamma(t'+\frac{ux'}{c^{2}})                        

but as x'=0 we just have:

t=\gamma(t')

t=1.67*5.00=8.35 s

b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.

I hope it helps you!

5 0
3 years ago
Read 2 more answers
What happens at the end of most cold currents?​
Akimi4 [234]

Answer:

Ocean currents act as conveyer belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off, thus influencing both weather and climate.

Explanation:

5 0
3 years ago
Read 2 more answers
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