<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
Step-by-step explanation:
Given expression is,
By using the law of logarithm,
By comparing exponents on both the sides of the equation,
Therefore, will be the answer.
Answer:
3x<u>></u><u>=</u><u> </u><u>21</u>
Step-by-step explanation:
Happy 2 Help. Hope you get a good grade lol
<span>
If BA is d units the CB must be 2d units. B is on the x-axis, 2d units
right of C so its coordinates are (2d, 0). A is d units above B at (2d,
d). </span>
The absolute value is the value of the number without the sign. So in this case it's 3 and -3
