You did not provide the tables to choose from, but the relationship between number of books and total price is that each book is 14.25. Hope that helps at least.

7 0

2 years ago

A construction company purchased some equipment costing $300,000. The value of the equipment depreciates

goldfiish [28.3K]

Answer:

$11.9\ years$

Step-by-step explanation:

we know that

The formula to calculate the depreciated value is equal to

$V=P(1-r)^{x}$

where

V is the depreciated value

P is the original value

r is the rate of depreciation in decimal

x is Number of Time Periods

in this problem we have

$P=\$300,000\\r=14\%=14/100=0.14\\V=\$50,000$

substitute the values and solve for x

$50,000=300,000(1-0.14)^{x}$

$(50,000/300,000)=(0.86)^{x}$

$(5/30)=(0.86)^{x}$

Apply log both sides

$log(5/30)=(x)log(0.86)$

$x=log(5/30)/log(0.86)$

$x=11.9\ years$

4 0

3 years ago

Read 2 more answers

How would you solve (4k+5)(k+1)=0?

alukav5142 [94]

$(4k+5)(k+1)=0\iff4k+5=0\ or\ k+1=0\\\\4k=-5\ or\ k=-1\\\\\boxed{k=-\frac{5}{4}\ or\ k=-1}$

5 0

3 years ago

Read 2 more answers