Range is all y-values. This would be all real numbers or (-oo,oo)
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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1- 13 or -13 (B)
2- -5 < y < -3 (A)
3- t = 6 or -6 (B)
Hope this helps you =)
Answer:
pls dont kill me for wacky lines. this shall just give you a basic idea. the important part is the 90° angle
Answer:
it decreases
Step-by-step explanation:
