For three hours is he will take up 5.25gallons.
she will be left with 4.75 gallons
Using the normal distribution, it is found that there is a 0.0548 = 5.48% probability that, in a given year, the rainfall is over 40 inches.
Normal Probability Distribution
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- Mean of 32 inches, so
. - Standard deviation of 5 inches, so
.
The probability that, in a given year, the rainfall is over 40 inches is <u>1 subtracted by the p-value of Z when X = 40</u>, so:



has a p-value of 0.9452.
1 - 0.9452 = 0.0548.
0.0548 = 5.48% probability that, in a given year, the rainfall is over 40 inches.
A similar problem is given at brainly.com/question/24663213
Answer:
1. b. 8 3/5
2. b. 3
3. 29
Step-by-step explanation:
1. b. 8 3/5
90 3/10 divided by 10 1/2
= 8 3/5
2. b. 3
8r= 24
/8 /8
r= 3
3. 29
957/33
= 29
You multiply the 2 values together and B is the correct answer
Answer:
91%
Step-by-step explanation:
hopes this helps