All categories

3 years ago

How do I solve 4x+23>-21

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

Answer:

Inequality Form:

x>-11

Step-by-step explanation:

Interval Notation:

(-11,\infty )

Karolina [17]3 years ago

4 0

Answer:

Step-by-step explanation:

4x + 23 > -21

4x > -21 -23 (moving 23 to the right side of equation changes the +23 to -23

4x > -44 (adding -21 to -23)

x > -11 (dividing both sides of equation by 4, this keeps the equation the same

Solution: x > -11 (x is greater than negative 11)

You might be interested in

Lily has 642 stamps in total. She has 54 US stamps than foreign stamps. How many does she have each

maw [93]

Answer:

answer in photo

hope this helps :)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

True or false.200centimeters=2meter

katovenus [111]

Answer:

Step-by-step explanation:

1 meter = 100 centimeters

therefore 2m = 2(100cm) = 200cm

6 0

3 years ago

S= 2m +2u <br><br> solve for m

Whitepunk [10]

M =0 if you put it in y= and hit 2nd graph and go down to the 0 there is a 1 with means m =0 (ti-84+ caculater)

6 0

3 years ago

A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the

amm1812

Answer:

$s(t)=(ln|7|+ln|2|)\,ft$

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

$a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\$

Integrating both sides w.r.to t

$v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\$

Using initial value

$v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}$

We have to calculate the distance covered in time interval [0,5], so:

$\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft$

3 0

3 years ago

What is the value of n?

mariarad [96]

Angles in straight line add to 180 degrees
180-142=38
180-133=47
180-38-47=95
180-95=85 degrees
B

5 0

2 years ago

Read 2 more answers