Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat
The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721
Answer:
Step-by-step explanation:
Answer:
The annual profits will be 2187.5
Step-by-step explanation:
p(x) = 65x - 0.3x^2
I am guessing that the 2 was supposed to be a square.
Simply plug in the number of pies sold:
p(175) = 65(175) - 0.3(175)^2 = 11375 - 0.3*30625 = 11375 - 9187.5 = 2187.5
Jasmine is running faster.
Since the track is 1/5 of a km and she can run 1km in 7 minutes, divide seven to get 1.4.
This means that Jasmine can run one lap in 1.4 minutes.
Since a Kyah can run 6 laps in 10 minutes, do 10 divided by 6 and the answe will be 1.6 repeating.
1.4 < 1.6 so Jasmine is faster
This is easy . There is a 20 percent discount which means now it’s only (100-20%) discount.
This is 80% discount.
Money saved is equal to 100-80%
=20%
And that 20% is equal to 13$ as per the passage.
So now we need to calculate 1 percent of the item without discount .
This is equal to 13/20
This is equal to .65
Now to find the original price you will need to multiply .65 to 100 this is equal to 65$.