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Zarrin [17]
2 years ago
12

On the provided graph, plot the points where the following function crosses the x-axis and the y-axis.g(x)=-5^(2)+5

Mathematics
1 answer:
maw [93]2 years ago
3 0

On the provided graph, plot the points where the following function crosses the x-axis and the y-axis will be (0, 4) and (1, 0).

<h3>What is a function?</h3>

A statement, principle, or policy that creates the link between two variables is known as a function.

The function is given below.

g(x) = -5ˣ + 5

The graph of the function is given below.

On the provided graph, plot the points where the following function crosses the x-axis and the y-axis will be (0, 4) and (1, 0).

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

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Given the parabola below, find the endpoints of the latus rectum. (x-2)^2=-20(y+2)
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Answer:

The endpoints of the latus rectum are (12, -7) and (-8, -7).

Step-by-step explanation:

A parabola with vertex at point C(x, y) = (h,k) and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

(x-h)^{2} = 4\cdot p \cdot (y-k) (1)

Where:

y - Independent variable.

x - Dependent variable.

p - Distance from vertex to the focus.

h, k - Coordinates of the vertex.

The coordinates of the focus are represented by:

F(x,y) = (h, k+p) (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that h = 2, k = -2 and p = -5, then the latus rectum is between the following endpoints:

By (2):

F(x,y) = (2, -2-5)

F(x,y) = (2,-7)

By (1):

(x-2)^{2} = -20\cdot (-7+2)

(x-2)^{2} = 100

x - 2 = \pm 10

There are two solutions:

x_{1} = 2 + 10

x_{1} = 12

x_{2} = 2-10

x_{2} = -8

Hence, the endpoints of the latus rectum are (12, -7) and (-8, -7).

4 0
3 years ago
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