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9966 [12]
2 years ago
12

I need help on how to do this

Mathematics
1 answer:
Leni [432]2 years ago
5 0

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

a) A system of equations has no solutions when the graphs of those equations do not intersect. If the equations are equations of a line, then the lines must be parallel in order for them not to intersect.

Any parallel line will do.

__

b) There is one solution when the graphs intersect in exactly one point.

Any line that crosses the one shown will do.

__

c) There are infinite solutions when the graphs describe the same curve.

A line overlapping the one shown is the one you want.

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BRAINLIEST if correct
Mekhanik [1.2K]
Okay so median is the number in the middle and mean is when you add them all up and divide by how many numbers there are 

<span>20,28,35,40,132 

So 35 is the median 
and the mean is </span>20 + 28 + 35 + 132 + 40 = 255 / 5 = 51

the mean is a better way to represent the data because it does not just pick a number from the set of numbers it calculates the average 
7 0
3 years ago
If these two shapes are similar, what is the measure of the missing length n?
scoundrel [369]

Answer:

39in.

Step-by-step explanation:

due to scale, cant be 15, as that would be the same length as other side

cant be 91 otherwise it wouldnt be similar if it had the same length as blue triangle which has 39 not 15 as the top side

3 0
2 years ago
Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7
r-ruslan [8.4K]
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
6 0
3 years ago
Please help, performance task: trigonometric identities
AnnZ [28]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<h3>How to solve the trigonometric equations?</h3>

<u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Read more about trigonometry equations at:

brainly.com/question/8120556

#SPJ1

4 0
1 year ago
Write a decimal that is 1/10 of .9
amm1812
1/10 of .9 is the same as dividing .9 by 10. .90 / 10 = .09 .09 is the answer
8 0
3 years ago
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