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MaRussiya [10]
3 years ago
7

Mr Stevenson has 160 cows goats horses and chickens on his farm 19 percent of the animals are cows 28 percent goats 13 percent h

orses and the rest are chickens how many chickens are on the farm
Mathematics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

64 Chickens

Step-by-step explanation:

1. Add up the percents

19% + 28% + 13% = 60%

2. Subtract from 100%

100% - 60% = 40%

3. Multiply the total number of animals by the percent of chickens

160 * .4 = 64 Chickens



-BARSIC- [3]3 years ago
6 0

Answer:

<u>64 chicken</u>

Step-by-step explanation:

160 x 0.19 = 30 cows if you (round)

160 x 0.28 = 45 goats if you (round)

160 x 0.13 = 21 horses if you (round)

19+28+13 = 60 percent out of  100, subtract 100%-60%= 40%

160 x 0.40 = 64 chickens.

To check you can do..

30+45+21= 96

Then you add 64 chicken to rest of the animals.

64 + 96 and you get all the animals.

So 64 is the answer.

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Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

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Step-by-step explanation:

Given

f(x) = 2x² + 5x - 12

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