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MaRussiya [10]
2 years ago
7

Mr Stevenson has 160 cows goats horses and chickens on his farm 19 percent of the animals are cows 28 percent goats 13 percent h

orses and the rest are chickens how many chickens are on the farm
Mathematics
2 answers:
castortr0y [4]2 years ago
7 0

Answer:

64 Chickens

Step-by-step explanation:

1. Add up the percents

19% + 28% + 13% = 60%

2. Subtract from 100%

100% - 60% = 40%

3. Multiply the total number of animals by the percent of chickens

160 * .4 = 64 Chickens



-BARSIC- [3]2 years ago
6 0

Answer:

<u>64 chicken</u>

Step-by-step explanation:

160 x 0.19 = 30 cows if you (round)

160 x 0.28 = 45 goats if you (round)

160 x 0.13 = 21 horses if you (round)

19+28+13 = 60 percent out of  100, subtract 100%-60%= 40%

160 x 0.40 = 64 chickens.

To check you can do..

30+45+21= 96

Then you add 64 chicken to rest of the animals.

64 + 96 and you get all the animals.

So 64 is the answer.

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Answer: 3/8

Step-by-step explanation:

1/2 × 3/4

Multiply the numerators: 1 × 3 = 3

Multiply the denominators: 2 × 4 = 8

I hope this is clear, have a great day.

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Step-by-step explanation:

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3 years ago
Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A drug is used to help prevent blood c
Alla [95]

Answer:

a) \hat p=\frac{148}{4167}=0.036

b) 0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030

0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041

Step-by-step explanation:

The sample proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part a

The estimated proportion for this case can be calculated like this:

\hat p=\frac{148}{4167}=0.036

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing we got:

0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030

0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041

8 0
3 years ago
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