Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
The answers be because it says DECREASED by 5 so it would be -5
Hi, i would love to help you but there is no graph below :(
Answer:
(x + 4)(2x - 3)
Step-by-step explanation:
Given
f(x) = 2x² + 5x - 12
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × -12 = - 24 and sum = + 5
The factors are + 8 and - 3
Use these factors to split the x- term
2x² + 8x - 3x - 12 ( factor the first/second and third/fourth terms )
2x(x + 4) - 3(x + 4) ← factor out (x + 4) from each term
(x + 4)(2x - 3)
Thus
f(x) = 2x² + 5x - 12 = (x + 4)(2x - 3) ← in factored form