Answer:
Let's try and figure it out yearly:
So for the first year the deposits would amount to 40 * 12 = $480
Now since the interest rate is applied yearly we will assume that the interest rate will be applicable to the amount that is left after the first year of deposits
So that would be 889.98 - 480 = 409.98
409.98 * 14.99 % = 61.45
The new amount owed for the second year would be 409.98 + 61.45 = 471.43
So by the end of the second year the debt would of been wiped clean with $8.57 to spare.
So the answer would be 24 months
Step-by-step explanation:
The graphs are curved, not segments ending in a point.
http://www.wolframalpha.com/input/?i=plot+y+%3D+sin+x+for+-3.2+%3C+x+%3C+3.2+and+-1.1+%3C+y+%3C+1.2
The old rate of pay is x and the new rate is y then we have:
y = 2x + 7
Y = 21
PART 1: 21 = 2x+7
Subtract 7 from each side:
14 = 2x
Divide both sides by 2:
X = 14 / 2
X = 7
PART 2: The internship pays $7 per hour.
Answer:
y = 4x + 8
Step-by-step explanation:
1) Find slope:
y2-y1/x2-x1
12-8/1-0 = 4/1 = 4
Slope = 4
2) Plug in a point in point-slope form
y-y1=m(x-x1)
y-8=4(x-0) =
y-8=4x-0 -> add 8 to both sides
y=4x+8
Answer:
im pretty sure the answer is d
Step-by-step explanation:
