3. 5mn ( 2m + 6n + 1 )
4. 4a^3b^2c ( 18a^2b - 8c )
5. (X-15)(X+15)
6. -4(y-4.5)(y+4.5)
8. 2X(X-10)(X+10)
i am not sure if no. 8 is right
Answer:
300miles per hour
Step-by-step explanation:
The coordinates of the image point are given to be B(4, -8). We are to find the coordinates of pre-image that is the coordinates before the translation.
The translation made was (x-2, y+3)
This means, the x coordinate was moved 2 units to left and y coordinate was moved 3 units above.
So, the coordinates of original point will be, 2 units to right of B and 3 units down of B.
So the coordinates will be (6, -11)
0 to 90 degrees is located in quadrant one. 90 to 180 degrees is located in quadrant two. 180 to 270 degrees is located in quadrant three. 270 to 360 degrees is located in quadrant four. Is this what you were after?
