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SVEN [57.7K]
3 years ago
9

HE:LPPPPPPPPPPPPPPP I GOT MORE SO CHECK MY PROFILE

Mathematics
2 answers:
kondaur [170]3 years ago
6 0

Answer:

21,000

Step-by-step explanation:

Round each number:

  1. 5,789 → 6,000
  2. 8,356 → 8,000
  3. 6,561 → 7,000

Add the rounded numbers:

  1. 6,000 + 8,000 + 7,000 = 21,000

I hope this helps!

denis23 [38]3 years ago
3 0

Answer:

21000

Step-by-step explanation:

To find estimate, round all the values to the nearest thousands

5,789 is 6000

8,356 is 8000

6,561 is 7,000

add.

6000+8000+7000

21000

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Frozen apple juice comes in a cylindrical can. A can is 12 cm high and has a radius of 3.5 cm. What is the capacity of the can?
34kurt

Answer:

438.501cm^3

Step-by-step explanation:

Given data

Height of can= 12cm

Radius= 3.5cm

The capacity of the can is expressed as

V= πr^2h

V= 3.14*3.5^2* 12

V= 3.14*12.25*12

V= 461.58cm^3

Hence the capacity is 461.58cm^3

We are also given that the juice amount to 95% of the capacity of the can

95/100*461.58= x

0.95*461.58=x

x=438.501cm^3

This means that the volume of the juice is 438.501cm^3

8 0
3 years ago
If my loan is 234,000 and my interest rate is 5% how much will my monthly payment be
zubka84 [21]

Answer:

4680 I think

Step-by-step explanation:

I divided your loan and interest rate by 5%

6 0
3 years ago
Could somebody give me the answer
Mamont248 [21]
Rewriting in intercept form
4x+6y= 3 becomes
y= 4x/6 + 3 /6 = ⅔x + ½
it's m = 2/3

for the second line
6x + 9y = 7
y= 6x/9 + 7/9 = ⅔x +7/9
it's m = 2/3

so the two lines are parallel..
100% sure ,

don't forget to give brainliest if correct
6 0
3 years ago
Look at attachment inside please help me im on timer
Julli [10]

4x { }^{2}  + 5 +  \frac{27}{x + 5}
3 0
4 years ago
How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=
\begin{cases}
-7\\
1
\end{cases}
\\\\\\
\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}
\\\\\\
x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
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