Answer:
(x+3)(x+4)(x-4)
x+2 and x-3 are not factors but x-4 is
Step-by-step explanation:
let's factor it :)
x^3 + 3x^2 - 16x -48
first we will factor this:
x^3 + 3x^2
x^2(x + 3)
then factor the second part :
- 16x - 48
-16(x + 3)
so now,
x^2(x + 3) - 16(x + 3)
factor out x+3
(x+3)(x^2 - 16)
factor x^2 - 16
(x+3)(x+4)(x-4)
2 angles are Complementary, if the sum of their measures = 90°.
Let the 2 angles be A and B, and let their measures be m(A)=a, m(B)=b.
Let A be the larger angle.
"the larger angle is six more than three times the smaller angle."
can be 'translated' into algebra as: a = 6 + 3b
Also, since A and B are complementary, we have a+b=90°.
substitute a=6+3b in the second equation:
a+b=90°
(6°+3b+b)=90°
4b=90°-6°
b=84°/4=21°
Then, a = 90°-21°=69°
Answer: a= 69°, b=21°
First, we will find the common difference
The common difference is ;
19 - 11 = 8
or
11 - 3 = 8
common difference is 8
As the position increase by 1, the result increase by 8
so we will keep on adding 8 to the result
Position Result
4 19
5 27
6 35
7 43
8 51
Hence;
when the position is 8, the result is 51
Answer:
(3,-4)
Step-by-step explanation:
3x+(first equation)=5
3x+(-x-1)=5
2x-1=5
x=3, solve for y;
y=-3-1, y=-4
Answer: No, an integer is a whole number that can be either negative or positive :)
Step-by-step explanation:
