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bagirrra123 [75]
2 years ago
8

If x=50.7,y=25.3 and z is defined as integer z,calculate z=x+y​

Computers and Technology
1 answer:
ANTONII [103]2 years ago
3 0

Answer:

Ans: 76

Explanation:

z=x+y

=50•7 + 25•3

=76#

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Answer:

Temporary Data

Explanation:

6 0
2 years ago
Tom teaches in a high school. He wishes to sort a spreadsheet containing students' marks in various subjects by descending order
cricket20 [7]

Answer:

Select the data to sort

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4 0
3 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
2 years ago
When you learned about the Highway Transportation system you learned about 6 different types of people as roadway users. Choose
Nimfa-mama [501]

<em><u>Answer:</u></em>

<em><u>1. Pedestrians - Most of pedestrians use to walk on the footpath along side road that keeps them on a safe side. But there are places without footpath along side road, in that case they have to walk on the road itself. Here, we need to take care for them. We need to wait in case they are crossing road and also check for them while taking a turn. </u></em>

<em><u> </u></em>

<em><u>2. Cyclists - They travel on road but are tough to figure out. They travel at a slower pace compared to cars. To avoid any accident with them, we are supposed to give them enough space which should be equivalent to a car's space. </u></em>

<em><u> </u></em>

<em><u>3. Motorcyclists - They can pass by very closely and also come between lanes. Most of the things to be considered here are same as that of cyclists. Here also, we need to check for them carefully while taking a turn. Also, need to give them enough space.</u></em>

<em><u>Explanation:</u></em>

5 0
2 years ago
Read 2 more answers
Jose has 3/5 kilogram of peppermints and 2/3 kilogram of candy canes. How many kilograms of candy does he have?
yarga [219]

Answer:

\frac{19}{15}\\

≅ 1.267

Explanation:

\frac{3}{5} +\frac{2}{3} \\\\= \frac{9}{15} + \frac{10}{15} \\\\= \frac{9+10}{15} \\\\= \frac{19}{15} \\\\= 1.267

6 0
2 years ago
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