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olga nikolaevna [1]

3 years ago

7

Ella is interested in combining substances to form a new material.

1 answer:

jolli1 [7]3 years ago

5 0

B. Have a good day:)

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How does the VSEPR theory explain molecular shape

natulia [17]

Answer:

to VSEPR theory, the shape of a molecule is related to the organization of the central atom's valence shell electrons. The valence shell electrons are all negatively charged and therefore are constantly repelling each other. This repulsion is what gives a molecule its three-dimensional shape.

3 0

3 years ago

Read 2 more answers

How many grams of a 14.0% (w/w) sugar solution contain 62.5<br> of sugar?

Delicious77 [7]

Answer:

$m_{solution}=446.4g$

Explanation:

Hello,

In this case, by-mass percent is computed in terms of the mass of the solute and the mass of the solvent as shown below:

$\% m=\frac{m_{solute}}{m_{solution}} *100\%$

Thus, solving for the mass of the solution, we obtain:

$\frac{x}{y} m_{solution}=\frac{m_{solute}}{\% m}*100\%\\ \\m_{solution}=\frac{62.5g}{14.0\%}*100\% \\\\m_{solution}=446.4g$

Regards.

3 0

3 years ago

When the volume and number of particles of a gas are constant which of the following is also constant

sineoko [7]

Answer:

The product of the pressure and volume.

3 0

3 years ago

Which of the following phrases best describes a synthesis reaction?

iogann1982 [59]

Answer is D breaking apart I to not more than two

4 0

4 years ago

The following reaction has Kp = 109 at 25°C. 2 NO(g) + Br2(g) equilibrium reaction arrow 2 NOBr(g) If the equilibrium partial pr

kati45 [8]

<u>Answer:</u> The equilibrium partial pressure of NO is 0.0034 atm

<u>Explanation:</u>

For the given chemical equation:

$NO(g)+Br_2(g)\rightleftharpoons 2NOBr(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{NOBr})^2}{p_{NO}\times p_{Br_2}}$

We are given:

Equilibrium partial pressure of $Br_2$ = 0.0159 atm

Equilibrium partial pressure of NOBr = 0.0768 atm

$K_p=109$

Putting values in above equation, we get:

$109=\frac{(0.0768)^2}{p_{NO}\times 0.0159}\\\\p_{NO}=0.0034atm$

Hence, the equilibrium partial pressure of NO is 0.0034 atm

3 0

3 years ago