Question

How many grams of a 14.0% (w/w) sugar solution contain 62.5 of sugar?

Answer 1

Answer:

$m_{solution}=446.4g$

Explanation:

Hello,

In this case, by-mass percent is computed in terms of the mass of the solute and the mass of the solvent as shown below:

$\% m=\frac{m_{solute}}{m_{solution}} *100\%$

Thus, solving for the mass of the solution, we obtain:

$\frac{x}{y} m_{solution}=\frac{m_{solute}}{\% m}*100\%\\ \\m_{solution}=\frac{62.5g}{14.0\%}*100\% \\\\m_{solution}=446.4g$

Regards.