The identity Sin(α)/Tan(α) = Cos(α) is valid
Trigonometry is study of triangles. All trigonometric ratios are defined using the sides of the right triangle, such as an adjacent side, opposite side, and hypotenuse side. Three major of them are as follows :-
Sine Function:
sin(θ) = Opposite / Hypotenuse
Cosine Function:
cos(θ) = Adjacent / Hypotenuse
Tangent Function:
tan(θ) = Opposite / Adjacent
Lets prove this identity by proceeding with the LHS
= Sin(α)/Tan(α)
= Sin(α)/ (Sin(α)/Cos(α)) (Tan(α) = Sin(α)/Cos(α))
= Sin(α)xCos(α) / Sin(α)
= Cos(α)
Hence verified
Learn more about Trigonometric Ratios here :
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Answer:
So then the minimum sample to ensure the condition given is n= 38
Step-by-step explanation:
Notation
represent the sample mean for the sample
population mean (variable of interest)
represent the population standard deviation
n represent the sample size
ME = 4 the margin of error desired
Solution to the problem
When we create a confidence interval for the mean the margin of error is given by this formula:
(a)
And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is
. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got
, replacing into formula (b) we got:
So then the minimum sample to ensure the condition given is n= 38
(2/3) / (1/9) = x / 1....2/3 day to 1/9 order = x days to 1 order
cross multiply
(1/9)(x) = (2/3)(1)
1/9x = 2/3
x = 2/3 * 9
x = 18/3
x = 6 days <==
The speed of wind is 656 kmph and speed of plane is 70 kmph.
<u>SOLUTION:
</u>
Given that, an air-plane travels 4688 kilometers against the wind in 8 hours
And 5808 kilometers with the wind in the same amount of time.
We have to find the rate of the plane in still air and the rate of wind
Now, let the speed of wind be a kmph and speed of plane be b kmph.
And we know that, 

Substituting (1) in (2) we get,


On substituting (3) in (1) we get,

Hence, the speed of wind is 656 kmph and speed of plane is 70 kmph.