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4 years ago

What second degree polynomial function f(x) has a leading coefficient of 3 and roots 4 and 1

Mathematics

1 answer:

Katena32 [7]4 years ago

4 0

Answer: f(x) = 3x² - 15x + 12

Step-by-step explanation:

Given f(x) has roots x = a and x = b, then

(x - a) and (x - b) are the factors

f(x) is then the product of the factors

f(x) = a(x - a)(x - b) ← where a is a multiplier

Given roots are x = 4 and x = 1, then

(x - 4) and (x - 1) are the factors

With a = 3, then

f(x) = 3(x - 4)(x - 1) ← expand factors using FOIL

= 3(x² - 5x + 4) ← distribute

= 3x² - 15x + 12

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4 years ago

Simultaneous equations 5x+y=28 x+y=2

ludmilkaskok [199]

Answer:

Step-by-step explanation:

$5x + y = 28$

$x + y = 8$

Solve the equation for y by moving 'x' to R.H.S and changing its sign

$5x + y = 28$

$y = 2 - x$

Substitute the given value of y into the equation 5x + y = 28

$5x + 2 - x = 28$

Solve the equation for x

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$4x + 2 = 28$

Move constant to R.H.S and change its sign

$4x = 28 - 2$

Subtract the numbers

$4x = 26$

Divide both sides of the equation by 4

$\frac{4x}{4} = \frac{26}{4}$

Calculate

$x = \frac{26}{4}$

Reduce the numbers with 2

$x = \frac{13}{2}$

Now, substitute the given value of x into the equation y = 2 - x

$y = 2 - \frac{13}{2}$

Solve the equation for y

$y = - \frac{9}{2}$

The possible solution of the system is the ordered pair ( x , y )

-------------------------------------------------------------

Let's check if the given ordered pair is the solution of the system of equation:

plug the value of x and y in both equation

$5 \times \frac{13}{2} - \frac{9}{2} = 28$

$\frac{13}{2} - \frac{9}{2} = 2$

Simplify the equalities

$28 = 28$

$2 = 2$

Since , all of the equalities are true, the ordered pair is the solution of the system.

$(x \:, y \: ) = ( \frac{13}{2} \: , - \frac{9}{2})$

Hope this helps....

Best regards!!

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