Answer:
The triangle with side lengths 7 in, 11 in, 13 in will be an acute angled triangle.
Step-by-step explanation:
If we assume that the triangle with height 7 inches and base 11 inches of a right triangle then its hypotenuse will have the length of
inches.
But the third side of the triangle is given to be 13 inches which is less than 13.04 inches i.e. 13 < 13.04.
Therefore, the triangle with side lengths 7 in, 11 in, 13 in will be an acute-angled triangle. (Answer)
D. AH
Segment AH is parallel to BD and if the lines were drawn out infinitely, the two lines would never meet.
Answer:
432 in.^2
Step-by-step explanation:
The side of the suitcase is a rectangle. One length is 24 inches. The diagonal of the rectangle is 30 inches long. The diagonal is a hypotenuse of a right triangle. The length is a leg. We need to find the other leg.
We use the Pythagorean theorem,
a^2 + b^2 = c^2
(24 in.)^2 + b^2 = (30 in.)^2
576 in.^2 + b^2 = 900 in.^2
b^2 = 324 in.^2
b = sqrt(324 in^2)
b = 18 in
area of rectangle = length * width
A = 24 in. * 18 in.
A = 432 in.^2
32,643/3=10,881 YES IT IS DIVISIBLE
32,643/9=3,627 YES IT IS DIVISIBLE
