The next two terms of the sequence 4,7,10,13 are...and ----
2 answers:
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Answer:
<u>The</u><u> </u><u>requ</u><u>ired</u><u> </u><u>num</u><u>ber</u><u> is</u><u> </u><u>7</u><u>0</u><u>.</u>
Step-by-step explanation:
let the no. be 10y + x where x is unit digit and y is ten's digit.
given , sum of the digit is 7
x + y = 7 ...(1)
also , reversing the no. we get 10x + y ,where x is ten's digit and y is unit digit.
given reversed digit decreases the number by 63 .
so, 10y + x - ( 10x + y ) = 63
9y -9x = 63
( dividing both side by 9 )
y - x = 7 ....(2)
adding 1 and 2 [ refer attachment ]
so the required original number is
10y + x = 10×7+0 = 70
Answer:
or
Step-by-step explanation:
We use casework on when and when
.
For the first case, , we add 9 to both sides to get
.
Dividing both sides by 3 gives
For the second case, , we add 9 to both sides to get
.
Dividing both sides by 3 gives
.
Checking both cases, we plug in and
.
For the first case, we have , which satisfies the equation.
For the second case, we have , which also satisfies the equation.
This gives us two solutions to the equation; and
.
Answer:
here's the Answer...see that
Step-by-step explanation:
