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Ivahew [28]
3 years ago
14

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.145 kg baseball crashing through the pane

of a second-floor window in a nearby building. The ball strikes the glass at 14.5 m/s , shatters the glass as it passes through, and leaves the window at 10.9 m/s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball
Physics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

J = -0.522 m/s

Explanation:

Given that,

The mass of the baseball, m = 0.145 kg

Initial velocity, u = 14.5 m/s

Final velocity, v = 10.9 m/s

aWe need to find the direction of the impulse that the glass imparts to the baseball. Impulse is equal to the change in momentum such that,

J=m(v-u)

Substitute all the values,

J=0.145\times (10.9-14.5)\\\\=-0.522\ kg-m/s

The direction of impulse is opposite to the direction of velocity.

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Identify where the sun's rays strike earth most directly and least directly
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Tropic of Capricorn. 

That's a belt around the Earth's "middle" called the "Tropic Zone". 
The equator is in the middle of it, the Tropic of Cancer is 23.5° North
of the equator, and the Tropic of Capricorn is 23.5° degrees South of it. 

The sun's rays can never be totally direct, straight down onto the Earth's
surface, anywhere outside this belt.


-- The sun's rays strike Earth least directly wherever, and whenever,
the sun is setting.
6 0
3 years ago
Please help I’ll give 15 points
ElenaW [278]

Answer:

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7 0
3 years ago
In the diagram, q1 = -6.39*10^-9 C and q2 = +3.22*10^-9 C. What is the electric field at point P? pls help
Alexxx [7]

Answer:

Below

Explanation:

First draw the vectors that represent both electric fields.

E1 is the elictric field created by q1, E2 is the one created by q2.

● q1 is negative so E1 will point from P.

● q2 is positive so E2 will point out of P

(Picture below)

■■■■■■■■■■■■■■■■■■■■■■■■■■

The resulting electric field is equal to the sum of the two fields since both vectors are colinear.

Let E be the total field.

● E = E1 + E2

The formula of the electric field intensity is:

● E = K ×(q/d^2)

-K is Coulomb's constant

-d is the distance between the charge and the object ( here P)

-q is the charge

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E1 = K × (q1/d1^2)

The distance between q1 and P is the qum of 0.15 m 0.25 m. (0.4 m)

Coulombs constant is 9×10^9 m^2/C^2

● E1 = 9×10^9 ×[-6.39 × 10^(-9)/ 0.4^2]

● E1 = -359.43 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E2 = K ×(q2/d^2)

The distance between q2 and P is 0.25 m.

● E2 = 9×10^9×[3.22×10^(-9) /0.25^2]

● E2 = 463.68 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E = E1 + E2

● E = -359.43+463.68

● E = 105.25 N/C

4 0
3 years ago
Read 2 more answers
A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19°C. When the balloon is released, it rises to an alti
inn [45]

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm  Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

3 0
3 years ago
A pendulum of length L = 1 m is released from an initial angle of 15° . After 1000 s, its amplitude is reduced to 2.5º. What is
jonny [76]

Answer:

The value of the time constant is 558.11 sec.

Explanation:

Given that,

Pendulum length = 1 m

Initial angle = 15°

Time = 1000 s

Reduced amplitude = 2.5°

We need to calculate the value of the time constant

Using formula of damping oscillation

\theta=\theta_{0}e^{\dfrac{t}{\tau}}

Where, \theta =amplitude

\theta_{0} =amplitude at t = 0

Put the value into the formula

2.5=15e^{\dfrac{-1000}{\tau}}

\dfrac{1}{6}=e^{\dfrac{-1000}{\tau}}

ln\dfrac{1}{6}=\dfrac{-1000}{\tau}

\tau=\dfrac{1000}{-ln\dfrac{1}{6}}

\tau=558.11\ sec

Hence, The value of the time constant is 558.11 sec.

6 0
3 years ago
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