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garik1379 [7]
3 years ago
10

A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19°C. When the balloon is released, it rises to an alti

tude where the pressure and temperature are 339 mm Hg and -55oC, respectively. What is the volume of the balloon (in L)
Physics
1 answer:
inn [45]3 years ago
3 0

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm  Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

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The answer is 40 kg. m/s.

Formula for momentum:

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So, therefore, the final answer is p=40 kg. m/s.

I hope this helped answer your question. Enjoy your day, and take care!

3 0
3 years ago
A research submarine has a 30-cm-diameter window that is 8.6cm thick. The manufacturer says the window can withstand forces up t
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6 0
3 years ago
Which equation states Newton's second law?
ohaa [14]

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6 0
3 years ago
Read 2 more answers
How do I solve number 2? Can someone please help?
Zigmanuir [339]

The rock is kicked horizontally off the cliff at 20 m/s.  

There's no air resistance, and gravity has no effect on horizontal motion.  There's no horizontal force acting on the rock to make it move horizontally slower or faster than 20 m/s, so it keeps moving horizontally at 20 m/s.

It's in the air for 7 seconds before it hits the ground.  Moving horizontally at 20 m/s for 7 seconds, it sails (20 x 7) = 140 meters horizontally away from the cliff.

5 0
4 years ago
Two identical small conducting spheres are separated by 0.60 m. The spheres carry different amounts of charge and each sphere ex
sergiy2304 [10]

Electrostatic force between two sphere is given by

F = \frac{kq_1q_2}{r^2}

here we know that

r = 0.60 m

F = 10.8 N

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now we will have

10.8 = \frac{9 \times 10^9 q_1q_2}{0.60^2}

since the two charges are attracting each other so here the two charges must be opposite in nature

q_1q_2 = -4.32 \times 10^{-10}

now we will use

q_1 - \frac{4.32 \times 10^{-10}}{q_1}= -24 \times 10^{-6}

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by solving above equation we will have

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so here we have net charge on each sphere is half of total charge

so we will have

q_1 = q_2 = -12\mu C

so force now is given as

F = \frac{9\times 10^9 (-12\times 10^{-6})^2}{0.60^2}

F = 3.6 N

this is repulsive force between two charges

5 0
3 years ago
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