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liraira [26]
3 years ago
10

Choose the correct simplification of the expression (2x7y)2(y5)3.

Mathematics
2 answers:
adoni [48]3 years ago
8 0

Im taking this to mean (2 x^7 y)^2 (y^5)^3


= 4x^14 y^2 * y^15


= 4x^14 y^17 which is option 4

olga55 [171]3 years ago
3 0

4x^14 y^17 which is option 4

I took the test

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Which value is NOT a solution of 8x3 – 1 = 0?
Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Step-by-step explanation:

Considering the equation

8x^3\:-\:1\:=\:0

Steps to solve the equation

8x^3-1=0

\mathrm{Add\:}1\mathrm{\:to\:both\:sides}

8x^3-1+1=0+1

\mathrm{Simplify}

x^3=\frac{1}{8}

\mathrm{Divide\:both\:sides\:by\:}8

\frac{8x^3}{8}=\frac{1}{8}

\mathrm{Simplify}

x^3=\frac{1}{8}

As

\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}

So,

x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}

Therefore,

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Keywords: solution, value

Learn more about equation solution from  brainly.com/question/1679491

#learnwithBrainly

7 0
3 years ago
Joelle is working on a school report in a word processor. She wants to place a figure which is 13.09 \text{ cm}13.09 cm13, point
dimulka [17.4K]
Subtract 13.09 from 21.59 giving you 8.5. Since the amount of space on both the left and right margin have to be equal you would divide by 2 to get 4.25 on the left margin as well as the right.
3 0
3 years ago
Read 2 more answers
5.06,5.14,5.1,5.01 smallest to largest​
beks73 [17]
5.01, 5.06, 5.14, 5.1
3 0
3 years ago
Which of the following are solutions to the quadratic equation? Check all that
xenn [34]

Step-by-step explanation:

I don't see options but here's the solution

2x²+9x-3=-x²+x

2x²+x²+9x-x-3=0

3x²+8x-3=0

(3x-1)(x+3)=0

Therefore x=⅓ or-3

6 0
2 years ago
Find the quotient of 4.13 x 10^-8 and 0.04 x 10^5. In two or more complete sentences, explain each step in your calculations.Inc
poizon [28]

we know that

Quotient is the number resulting from the division of one quantity by another

Let

x--------> the first quantity

y------> the second quantity

q------> the quotient

So

q=\frac{x}{y} -------> equation 1

in this problem

x=4.13*10^{-8} \\ y= 0.04*10^{5}

Substitute the values in the equation 1

q=\frac{4.13*10^{-8}}{0.04*10^{5}}

Simplify

q=\frac{4.13*10^{-8}}{0.04*10^{5}}=\frac{4.13}{0.04}*10^{-8}*10^{-5}=\frac{4.13}{0.04}*10^{-13}\\ \\q=103.25*10^{-13}\\ \\q= (1.0325*10^{2})*10^{-13}\\ \\q= 1.0325*10^{-11}

therefore

<u>the answer is</u>

The quotient is equal to 1.0325*10^{-11}

6 0
3 years ago
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