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3 years ago

Which inequality is the solution to 20+2 < Ž -8?

Mathematics

1 answer:

Maru [420]3 years ago

5 0

Answer:

the 20 +2

Step-by-step explanation:

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Solve the differential equation. y' + 5xey = 0.

galben [10]

Answer:

The solution is $y = - ln(\frac{5}{2}x^{2} + C)$

Step-by-step explanation:

To solve the differential equation, we will find $y$

From the given equation, y' + 5xey = 0.

That is, $y' + 5xe^{y} = 0$

This can be written as

$\frac{dy}{dx} + 5xe^{y} = 0$

Then,

$\frac{dy}{dx} = - 5xe^{y}$

$\frac{dy}{e^{y}} = - 5x dx$

Then, we integrate both sides

$\int {\frac{dy}{e^{y}}} =\int {- 5x dx}$

$\int {e^{-y}dy }} =\int {- 5x dx}$

Then,

$-e^{-y} = -\frac{5}{2}x^{2} + C$

$e^{-y} = \frac{5}{2}x^{2} + C$

Then,

$ln(e^{-y}) = ln(\frac{5}{2}x^{2} + C)$

Then,

$-y = ln(\frac{5}{2}x^{2} + C)$

Hence,

$y = - ln(\frac{5}{2}x^{2} + C)$

5 0

3 years ago

Complete each function table,then graph the function

babunello [35]

The y values from:

1. ₋6

2. ₋3

3. 0

4. 3

Given the x values and y value as y = 3x

1. when x = ₋2 then y = 3x

y = 3(₋2)

y = ₋6

2. when x = ₋1 then y = 3x

y = 3(₋1)

y = ₋3

3. when x = 0 then y = 3x

y = 3(0)

y = 0

4. when x = 1 then y = 3x

y = 3(1)

y = 3

therefore we get the points as (₋2 , ₋6) (₋1 , ₋3) (0,0) (1 , 3).The graph is pltted and attached.

Learn more about Coordinate geometry here:

brainly.com/question/11234618

#SPJ9

7 0

2 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

Solve (5y+2)(y+2)=3(5y+2)

DiKsa [7]

Answer:

y=1, y=-2/5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please answer this correctly

Contact [7]

Answer:

3 4, 5 0 6

Step-by-step explanation:

88,946 - 54,440 = 34,506

So missing number :

3 4, 5 0 6

8 0

3 years ago

Read 2 more answers