Option a is correct. The calculated answer is 0.150
<h3>How to get the value using the cdf</h3>
In order to get P(0.5 ≤ X ≤ 1.5).
This can be rewritten as
p = 0.5
and P = 1.5
We have the equation as

This would be written as
1.5²/16 - 0.5²/16
= 0.1406 - 0.015625
= 0.124975
This is approximately 0.1250
Read more on cdf here:
brainly.com/question/19884447
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<h3>complete question</h3>
Use the cdf to determine P(0.5 ≤ X ≤ 1.5).
a) 0.1250
b) 0.0339
c) 0.1406
d) 0.0677
e) 0.8750
f) None of the above
Number D is the correct answer I think
Answer:
365 messages
Step-by-step explanation:
x = # text messages)
16.5 = 10 + .10(x - 300)
6.5 = .10x - 30
36.5 = .10x
x = 365
Answer:
its the equal sign which the hip hop give me a pop says the equations equal
Step-by-step explanation:
Answer:
110.5348 minutes
Step-by-step explanation:
The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...
Δt = 103×(59/103)^(t/46)
We want to find t for the temperature difference Δt = 91 -64 = 27.
27 = 103×(59/103)^(t/46)
27/103 = (59/103)^(t/46) . . . . . divide by 103
Taking logs gives the linear equation ...
log(27/103) = (t/46)log(59/103)
Multiplying by the inverse of the coefficient of t, we get ...
t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)
≈ 110.5347
It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.
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<em>Comment on 4 decimal places</em>
An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.
More realistic would be an answer to 4 <em>significant figures</em>, a tenth of a minute and a few hundredths of a degree.
(The rate of change at the time of interest is about -0.33 degrees per minute.)