Answer:
3.8 ; 3.79 ; 3
Step-by-step explanation:
Given that:
1 gallon is equal to about 3.785 litres
3.785 to the nearest tenth :
Tenth digit = 7 ; round up 8 to 1 and add to 7
Hence,
3.785 = 3.8 (nearest tenth)
3.785 to the nearest hundredth :
Hundredth digit = 8 ; round up next digit 5 to 1 and add to 8
3.785 = 3.79 ( nearest hundredth)
What is the greatest number of whole liters of water you could pour into a one-gallon container without it overflowing?
The greatest Number of whole liters of water that could be poured into a 1 gallon container without it overflowing is 3 liters because, rounding up 3.785 to the nearest integer of 4 means we will exceed the maximum litres by about 0.215 gallons and hence, cause the container to overflow.
Answer:
1/6
Step-by-step explanation:
Answer:
11 hours
Step-by-step explanation:
Setting up a system of equations and using the substitution method will give you the number of hours used by each tap. Let a = time for tap A and b = time for tap B:
a + b = 12 (A and B fill a tank in 12 hours)
a = b - 10 (tap A takes 10 hours less than tap B)
Substitute 'b - 10' for 'a' in the first equation:
b - 10 + b = 12
Combine like terms: 2b - 10 = 12
Add 10 to both sides: 2b - 10 + 10 = 12 + 10 or 2b = 22
Divide by 2: 2b/2 = 22/2
Solve for b: b = 11 hours
A dodecagon is the answer
X = t - 3 is also -t = -x - 3 or t=x+3
Substitute it in
y=2/t+5
y=2/(x+3)+5
Let y=0 to solve for x
0=2/(x+3)+5
-5= 2/(x+3)
-10=x+3
-7=x
Now solve for t
t = x+3
t = (-7)+3
t = -4
Now we can solve for y
y = 2/(-4)+5
y = -0.5+5
y = 4.5
To check
4.5 = 2/(-4) + 5
4.5 = -0.5 + 5
4.5 = 4.5
-7 = -4 - 3
-7 = -7
Therefore
x = -7
y = 4.5
t = -4