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3 years ago

I love glee who else does and no i am not a child

Advanced Placement (AP)

2 answers:

7nadin3 [17]3 years ago

7 0

Answer:
Yes! Love it :)

soldi70 [24.7K]3 years ago

4 0

Answer:

My sister does but I don't watch it

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In Africa, parasitic diseases such as malaria are most likely to occur and spread in __________ regions near the Equator.

AVprozaik [17]

Answer:

Tropical or warmer

Explanation:

The warmth and humidity in tropical regions, like near the equator, allow parasitic diseases to thrive among the immense insect population and rich, fertile soils.

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3 years ago

Read 2 more answers

FOR 38 POINTS !!!

devlian [24]

Its C i have been in civic this whole year

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3 years ago

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1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

2 years ago

The transition from desirable ethics to internal values to actual behaior is

Rufina [12.5K]

The transition from desirable ethics to internal values to actual behavior is internalization of ethical issues and looking inward to ones values.

8 0

3 years ago

Which of the following pairs of angles is not necessarily congruent

Alex

Answer:

E. $\angle 3$ and $\angle 5$ .

Explanation:

According to the figure, we have the following conclusions:

1) $\angle 1$ and $\angle 2$ are vertical opposite angles. ( $m \angle 1 = m \angle 2$ )

2) $\angle 2$ and $\angle 3$ are internal alternate angles. ( $m \angle 2 = m\angle 3$ )

3) $\angle 2$ and $\angle 4$ are corresponding angles. ( $m\angle 2 = m\angle 4$ )

4) $\angle 3$ and $\angle 4$ are vertical opposite angles. ( $m \angle 3 = m \angle 4$ )

But, $\angle 3$ and $\angle 5$ , since $m \angle 3 + m\angle 6 + m\angle 5 = 180^{\circ}$ , where $\angle 3$ is an acute angle and $\angle 6$ is a right angle, and $m \angle 4 + m \angle 5 = 90^{\circ}$ . Then,

$m\angle 5 = 90^{\circ} -m\angle 4$ .

$m\angle 5 = 90^{\circ}-m\angle 3$

Hence, the right answer is E.

8 0

3 years ago