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Irina18 [472]
3 years ago
9

Find p if x=-3 is a factor of 2x³- 2px² + p + 2​

Mathematics
1 answer:
irina [24]3 years ago
4 0

Answer:

2x³- 2px² + p + 2

First plug in x = -3

2(-3)³- 2p(-3)² + p + 2

According to PEMDAS, we should solve the exponents first.

(-3)³ = -27

(-3)² = 9

2(-27) - 2(9)p + p + 2

Now multiply.

-54 - 18p + p + 2

Now combine the variables and constants.

-17p - 52

This is the simplified expression.

If it is an equation, then it would equal 0.

-17p - 52 = 0

To solve for p, add 52 to both sides.

-17p = 52

Now isolate the p by dividing by -17.

p = -52/17 or -3.0589

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<img src="https://tex.z-dn.net/?f=3x%2B18x-27%3D0" id="TexFormula1" title="3x+18x-27=0" alt="3x+18x-27=0" align="absmiddle" clas
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I. 6x2 + 25x + 24 = 0 6x2 + 16x + 9x + 24 = 0 2x (3x +8) + 3 (3x + 8) = 0 (2x + 3) (3x +8) ... < y=1; = x<y I. 10x2 + 33x + 27 = 0 => 10x2 + 15x + 18x + 27 = 0 => 5x (2x + 3) + 9 (2x + 3) = 0 => (5x +9) (2x +3) ... x = —9/5, –3/2 II. ... (b) 62 (d) is TX TX II.

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