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3 years ago

Please help!! I need to go to the next question!

Mathematics

1 answer:

tino4ka555 [31]3 years ago

5 0

Given:

The inequality is:

$3t+1\leq 5$

To find:

The graph of the given inequality.

Solution:

We have,

$3t+1\leq 5$

Subtract both sides by 1.

$3t\leq 5-1$

$3t\leq 4$

Divide both sides by 3.

$t\leq \dfrac{4}{3}$

The value of t is less than or equal to $\dfrac{4}{3}$ .

Since $t\leq \dfrac{4}{3}$ , it means $\dfrac{4}{3}$ is included in the solution, therefore there is a closed circle at $t=\dfrac{4}{3}$ and an arrow approaches to left from $t=\dfrac{4}{3}$ .

Therefore, the correct option is A.

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If you multiply two binomials together, and get a Trinomial, factoring the Trinomial would undo the multiplication, and you woul

melisa1 [442]

Answer: False
I hope this helps you !

4 0

3 years ago

(System of inequality word problem.)

lana66690 [7]

Answer:

Step-by-step explanation:

Because nintendo price=300$

He has 215$

1 chore he does=7$

Meaning if he did 10 chores he get's 70$ added so he did 10 now he has 285$ If he does 2 more chores that is 14$ more added.

So he now has 299$ so he done 12 chores and he needs 1 more dollar so if he did 1 more he gets 306$ and that was the least amount of chores he could do if he wanted 300$

And there's your answer

Hope this helps have a awesome day:)

8 0

2 years ago

A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla

Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

$\frac{4}{12} * \frac{8}{11} = \frac{32}{132}$ or 0.2424 or 24.24%

8 0

3 years ago

Evaluate the square root of x^2 - 5x when x = 7. Round your answer to the nearest hundredth

Troyanec [42]

X^2-5x, given x=7,

(7)^2-5(7)=14

sqrt(14)=3.74

5 0

3 years ago

Read 2 more answers

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

3 years ago