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2 years ago

5

Please help!! I need to go to the next question!

1 answer:

tino4ka555 [31]2 years ago

5 0

Given:

The inequality is:

$3t+1\leq 5$

To find:

The graph of the given inequality.

Solution:

We have,

$3t+1\leq 5$

Subtract both sides by 1.

$3t\leq 5-1$

$3t\leq 4$

Divide both sides by 3.

$t\leq \dfrac{4}{3}$

The value of t is less than or equal to $\dfrac{4}{3}$ .

Since $t\leq \dfrac{4}{3}$ , it means $\dfrac{4}{3}$ is included in the solution, therefore there is a closed circle at $t=\dfrac{4}{3}$ and an arrow approaches to left from $t=\dfrac{4}{3}$ .

Therefore, the correct option is A.

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HELPPPPPPP!!!!!!! Plz

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The answer is to this question is a)strong positive...

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3 years ago

Factor 27b - 18.<br> Write your answer as a product with a whole number greater than 1.

ElenaW [278]

9(3b-2) Iv factorised it but I dont know the rest sorry

3 0

3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago

Use the table to determine whether the relationship is proportional. If so, write an equation for the relationship. Tell what ea

Rudik [331]

Answer:

3 is not 4 is proportional

Step-by-step explanation:

8 0

2 years ago

A standard six-sided die is rolled twice and the top faces are observed. What is the probability that the sum of the numbers on

melisa1 [442]

<u>Answer: </u>

A standard six-sided die is rolled twice and the top faces are observed and the probability that the sum of the numbers on the top faces is 10 is $\frac{1}{12}$

<u>Solution: </u>

The sample space of two dice outcomes is given as follows:

{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3, 1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4, 1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5, 1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6, 1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of events n(s) = 36

Expected Outcomes = {(4, 6), (5, 5), (6, 4)}

Number of favorable outcomes n(E) = 3

Probability (sum of numbers on the top faces is 10) = $\frac{n(E)}{n(s)}$ = $\frac{3}{36}$ = $\frac{1}{12}$

Therefore the probability that the sum of the numbers on the top faces is 10 is $\frac{1}{12}$

3 0

3 years ago