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2 years ago

Rewrite the expression in the form y^n. (y^-1/2)^4

Mathematics

2 answers:

meriva2 years ago

7 0

Answer:

y^ -2

Step-by-step explanation:

We know that a^b^c = a^(b*c)

(y^-1/2)^4

y^(-1/2*4)

y^ -2

Dmitriy789 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

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3 years ago

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The table shows a function. Is the function linear or nonlinear?

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Answer:

nonlinear

Step-by-step explanation:

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2 years ago

Which step should be completed first in the following problem 4(27÷3²)

Yakvenalex [24]

Answer:

3²

Step-by-step explanation:

We have to use BPEMDAS Order of Operations:

B - Brackets

P - Parenthesis

E - Exponents

M - Multiply

D - Divide

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We use this order left to right. Since we have parenthesis, we look at that first. Inside, we have division and exponents. Since exponents come first, we have to evaluate 3² first.

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3 years ago

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Which graph best represents the following situation?

hichkok12 [17]

Answer:

The correct option is D. The situations x increases, y decreases; r= -0.41 is represented by Graph D.

Step-by-step explanation:

Given information: x increases, y decreases; r= -0.41.

Here r represents the correlation between two variables x and y.

If r is close to -1, then it is strong negative correlation.

If r is close to 1, then it is strong Positive correlation .

If r is close to -0.5, then it is weak negative correlation.

If r is close to 0.5, then it is weak positive correlation .

If r=0, then there is no correlation between x and y.

In graph A, x increases, y decreases and r is close to -1 because it is strong negative correlation.

Therefore option A is incorrect.

In graph B, x increases, y increases and r is close to 0.5 because it is weak positive correlation.

Therefore option B is incorrect.

In graph C, x increases, y increases and r is close to 1 because it is strong positive correlation.

Therefore option C is incorrect.

In graph A, x increases, y decreases and r is close to -0.5 because it is weak negative correlation.

Therefore option D is correct.

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2 years ago

Read 2 more answers

X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square

swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = $-\frac{4}{5}x+\frac{58}{5}$

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

[x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

(x + 2)² + (y - 5)²- 29 + 20 = 30

(x + 2)² + (y - 5)²- 9 = 30

(x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

Slope of the line joining this point to the center (-2, 5),

$m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{10-5}{2+2}$

= $\frac{5}{4}$

Let the slope of the tangent which is perpendicular to this line is ' $m_{2}$ '

Then by the property of perpendicular lines,

$m_{1}\times m_{2}=-1$

$\frac{5}{4}\times m_{2}=-1$

$m_{2}=-\frac{4}{5}$

Now the equation of the line passing though (2, 10) having slope $m_{2}=-\frac{4}{5}$

y - y' = $m_{2}(x-x')$

y - 10 = $-\frac{4}{5}(x-2)$

y - 10 = $-\frac{4}{5}x+\frac{8}{5}$

y = $-\frac{4}{5}x+\frac{8}{5}+10$

y = $-\frac{4}{5}x+\frac{58}{5}$

Therefore, equation of the line will be, y = $-\frac{4}{5}x+\frac{58}{5}$

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3 years ago