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nasty-shy [4]
3 years ago
5

What is the value of the expression when p = 7? 9p-7 A. 12 B.27 C.36 D.60

Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

56

Step-by-step explanation:

Just substitute 7 for p in the expression 9p - 7:  9(7) - 7 = 56

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PLEASE HELP!!! I WILL MARK BRAINLEST!!!
storchak [24]

Answer:

Each hat is $5

Each mask is $3

Step-by-step explanation:

Hat= x dollars

Mask= y dollars

Now,

3 hats and 4 mask sold = $27

We can write

3x + 4y = 27

Adding the second equation (-1 times 1st equation) gives us;

3x + 6y = 33

-1* (3x + 4y = 27)

3x + 6y = 33

-3x -4y = 27

2y = 6

y = 6/2

***y = 3***

Now we replace y= 3 into 1st equation and solve for x:

3x + 4y = 27

3x + 4(3) = 27

3x + 12 = 27

3x + 15

x = 15/3

***x= 5***

Each hat costs $5

Each mask costs $3

6 0
3 years ago
PLEASE HELP THIS IS DUE BY TOMORROW
Bezzdna [24]

Answer:b

Step-by-step explanation:

4 0
3 years ago
The sequence a1 = 6, an = 3an-1 can also be written as
wariber [46]
The question as presented is incomplete, here is the complete question with the multiple choice:

The sequence a1 = 6, an = 3an − 1 can also be written as:

1) an = 6 ⋅ 3^n
2) an = 6 ⋅ 3^(n + 1) 
3) an = 2 ⋅ 3^n
4) an = 2 ⋅ 3^(n + 1)

The correct choice is option 3) an = 2⋅3^n.

If we look at the initial sequence an = 3⋅an-1, and

a1 = 3⋅a0 = 6
a0 = 6/3
a0 = 2

We can now look at the sequence.

a0 = 2
a1 = 6
a2 = 18
a3 = 54
etc...

A common factor in each of those numbers is 2, so we can rewrite the sequence by factoring out 2.

a0 = 2⋅1
a1 = 2⋅3
a2 = 2⋅9
a3 = 2⋅27

The numbers being multiplied by 2 are all factors of 3. So we can rewrite the sequence again as:

a0 = 2⋅3^0
a1 = 2⋅3^1
a2 = 2⋅3^2
a3 = 2⋅3^3

This sequence can now be rewritten as an = 2⋅3^n.
7 0
3 years ago
the tigers won twice as many football games as they lost. they played 96 games. how many games did they win?
alukav5142 [94]
Half of 96 is 48 and they won twice as many as they lost.. how can this math problem be real XD
7 0
3 years ago
the sum of 3 consecutive integers is 29 less than 5 times the smallest number. find the three numbers
allochka39001 [22]

x + x + 1 + x + 2 = 5x - 29

Combine like terms.

3x + 3 = 5x - 29

Subtract 3x from both sides.

3 = 2x - 29

Add 29 to both sides.

32 = 2x

Divide both sides by 2.

16 = x

<h3>The first digit is 16.</h3><h3>The second digit is 17.</h3><h3>The third digit is 18.</h3>
6 0
3 years ago
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