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djverab [1.8K]
2 years ago
15

A factory robot recently examined some bulbs, of which 12 were flawed and 48 were not. Considering this data, how many flawed bu

lbs would the robot be expected to find in a batch of 95 bulbs?
Mathematics
1 answer:
NeX [460]2 years ago
7 0

Using the expected value of the binomial distribution, it is found that the robot would be expected to find 19 flawed in a batch of 95 bulbs.

For each bulb, there are only two possible outcomes, either it is defective, or it is not. The probability of a bulb being defective is independent of any other bulb, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution? </h3>
  • The <em>binomial distribution</em> is the <u>probability of exactly x successes on n repeated trials, with p probability of a success on each trial</u>.

The expected value is given by:

E(X) = np

In this problem:

  • Out of 12 + 48 = 60 bulbs, 12 were flawed, hence p = \frac{12}{60} = 0.2.
  • A batch of 95 bulbs is taken, hence n = 95.

Then, the <em>expected value </em>is:

E(X) = np = 95(0.2) = 19

The robot would be expected to find 19 flawed in a batch of 95 bulbs.

To learn more about the binomial distribution, you can take a look at brainly.com/question/26155596

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Musya8 [376]
Let x=ab=ac, and y=bc, and z=ad.

Since the perimeter of the triangle abc is 36, you have:

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The triangle is isosceles (it has two sides with equal length: ab and ac). The line perpendicular to the third side (bc) from the opposite vertex (a), divides that third side into two equal halves: the point d is the middle point of bc. This is a property of isosceles triangles, which is easily shown by similarity.

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36 + 2z = 60 => 2z = 60 - 36 => 2z = 24 => z = 12

The measure of ad is 12.

If you prefer a less algebraic reasoning:

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ad = 30 - (36/2) = 30 - 18 = 12
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Let n be the number. The difference of the number and six is n-6. Then three times the difference of the number and six is 3·(n-6). This number 3·(n-6) increased by four times the number n, then

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