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3 years ago

Help plzzz on both looooooooooooooooll

Mathematics

1 answer:

zloy xaker [14]3 years ago

3 0

Answer:

the answer is yes hope this helps you

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Graph the function y = 4x4 - 8x2 + 4. Which lists all of the turning points of the graph? 0 (0,4) 0 (-1,0) and (1, 0) 0 (-1,0),

jeyben [28]

Answer:

(-1,0) (0,4) (1,0)

Step-by-step explanation:

The turning points are also called the critical points. It is where the graph changes direction.

They occur at (-1,0) (0,4) (1,0)

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3 years ago

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Three integers between -4 and 0

balu736 [363]

Integers between -4 and 0 are : -3, -2, and -1

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In how many ways can you distinguishable ways can you arrange the letters AAABB

anyanavicka [17]

Answer:

Step-by-step explanation:

5! divided by all the repeats so 3!2! = 10 ways

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3 years ago

The exact value of cos5pi/12 is:

jonny [76]

Step 1: Convert $\frac{5\pi }{12}$ , which is in radians into degrees. To convert it multiply by $\frac{180}{\pi }$

$\frac{5\pi }{12} =\frac{180}{\pi }$

900/12

Step 2: 75 degrees isn't on the unit circle but 45 degrees and 30 degrees is. Since 45 + 30 = 75 you can use the cosine of 45 and 30 to find the exact value

cos45 = $\frac{\sqrt{2} }{2}$

cos30 = $\frac{\sqrt{3} }{2}$

Step 3: Add the cos45 and cos30 to get cos5pi/12

$\frac{\sqrt{2} }{2} +\frac{\sqrt{3} }{2} = \frac{\sqrt{2}+\sqrt{3}}{2}$

Hope this helped!

4 0

3 years ago

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$

Since tan is negative in the second quadrant. Hence,

$\large{ \cancel{ tan \theta = \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta = - \frac{ \sqrt{5} }{2} }}$

Answer

tan = -√5/2

3 0

3 years ago