Answer:
<h3>a.China - 52</h3>
<h3>b.Malaysia - 76</h3>
<h3>c.Singapore - 57</h3>
<h3>Will You Be My Friend?</h3>
<h3>Plz mark Me brainliest Dear☺☺</h3>
ion even know yet
gyfujkl;kjbhvgfcdxsrtuiokl;, nbvghjkjhbgyu
<span><span>(<span>6−d</span>)</span><span>(<span><span><span>d^2</span>−5</span>+<span>3d</span></span>)</span></span><span>=<span><span>(<span>6+<span>−d</span></span>)</span><span>(<span><span><span>d^2</span>+<span>−5</span></span>+<span>3d</span></span>)</span></span></span><span>=<span><span><span><span><span><span><span>(6)</span><span>(<span>d^2</span>)</span></span>+<span><span>(6)</span><span>(<span>−5</span>)</span></span></span>+<span><span>(6)</span><span>(<span>3d</span>)</span></span></span>+<span><span>(<span>−d</span>)</span><span>(<span>d^2</span>)</span></span></span>+<span><span>(<span>−d</span>)</span><span>(<span>−5</span>)</span></span></span>+<span><span>(<span>−d</span>)</span><span>(<span>3d</span>)</span></span></span></span><span>=<span><span><span><span><span><span>6<span>d^2</span></span>−30</span>+<span>18d</span></span>−<span>d^3</span></span>+<span>5d</span></span>−<span>3<span>d^2</span></span></span></span><span>
=<span><span><span><span> −<span>d3^</span></span>+<span>3<span>d^2</span></span></span>+<span>23d</span></span>−<span>30</span></span></span>
<span>
</span>
Answer:
25%
Step-by-step explanation:
Assuming that each child can only be a boy or a girl, then each child will have a probability of 0.5 or 50% of being either gender. Therefore, since we need to find the probability of at least 2 being boys then we simply need to multiply this probability twice.
0.50 * 0.50 = 0.25 or 25%
Using this data we can say that there is a 25% probability of there being at least 2 boys in the family.
The answer is 14 + x = 17
