(a) what are the x and y components of each vector?
For vector v1:
v1 = 6.6 (cos (180) i + sine (180) j)
v1 = 6.6 (-1i + 0j)
v1 = -6.6i
For vector v2:
v2 = 8.5 (cos (55) i + sine (55) j)
v2 = 8.5 ((0.573576436) i + (0.819152044) j)
v2 = 4.88 i + 6.96 j
(b) determine the sum v v 1 2
The sum of both vectors is given by:
v1 + v2 = (-6.6i) + (4.88 i + 6.96 j)
Adding component to component:
v1 + v2 = (-6.6 + 4.88) i + (6.96) j
v1 + v2 = (-1.72) i + (6.96) j
Answer:
6
Step-by-step explanation:
put unknown as y
area of rectangle = width × long
y(y - 2)=48
y² -2y =48
u can use scientific calculator to find this
y²-2y-48=0
(y-8)(y+6)=0
y=8 y=-6
take the positive value and ignore the negative value
width=y-2 long=8
8-2=6
I hope this help you :)
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
Answer:
The answer should be BAD
Step-by-step explanation:
They are all parallel from each other and will never touch
None
6 x 3
6^3
6 x 3
None
3^6
