Answer: Option A
or
Step-by-step explanation:
Use the quadratic formula to find the zeros of the function.
For a function of the form

The quadratic formula is:

In this case the function is:

So

Then using the quadratic formula we have that:



Remember that 




or

First in factoring, you must find out what is common in the whole equation

Now, make 2 sets of parentheses and "split up" the rest of the equation
Try to experiment which numbers work out
We are not subtracting anything so both parentheses are positive

Therefore, the factored version of

is
Answer: False
Step-by-step explanation:
4x - (5y) 2 = 64x - (5y) 2 = 6
Identify the variables:
4x, 5y, 64x
So, it would actually be:
4, 5, and 64
Answer:
f(f(5)) = 11
Step-by-step explanation:

I hope that is useful for you
60 onces is 15lbs so then i beleve you have 11lbs too much