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3 years ago

6

Write 1,334,457. in 12 expanded form

1 answer:

Alchen [17]3 years ago

8 0

1,000,000+3000,000+30,000+4,000+400+50+7

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I need help please this due tomorrow

OLEGan [10]

<em>What do you need help with on your homework. You need all the answers?</em>

<em>My friend. I am a teacher at a middle school</em>

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3 years ago

Find the coordinates of point B along a directed line segment from A(3,4) and

andreev551 [17]

We have been given two points. $A(3,4)$ and $C(3,9)$ . We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.

We will use segment formula to solve our given problem.

When a point P divides segment any segment internally in the ratio $m:n$ , then coordinates of point P are:

$[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]$

$(x_1,y_1)=(3,4)$ and $(x_2,y_2)=(3,9)$ .

$m=4,n=1$

Upon substituting our given information in above formula, we will get:

$[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]$

$[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]$

$[\right x=\frac{15}{5},y=\frac{40}{5}\left]$

$[\right x=3,y=8\left]$

Therefore, the coordinates of point B would be $(3,8)$ .

8 0

3 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

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3 years ago

What's the radius of a circle with an area of 64 square feet?

Tpy6a [65]

The answer is 4.51.............

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3 years ago

Read 2 more answers

HELP! WILL GIVE BRAINLEST!

bulgar [2K]

Answer:

A

Step-by-step explanation:

tan theta will equal zero if theta = n × pi where n is an integer

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2 years ago