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irakobra [83]
3 years ago
8

The energy used to move against the magnetic force is stored as (pick one: potential or kinetic)

Physics
1 answer:
sukhopar [10]3 years ago
6 0
I would pick potential
You might be interested in
M
cupoosta [38]

Answer:

<h3>The answer is 1.92 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 2.5 g

Volume = 1.3 cm³

We have

density =  \frac{2.5}{1.3}  \\  = 1.923076...

We have the final answer as

<h3>1.92 g/cm³</h3>

Hope this helps you

5 0
3 years ago
Why are some substances gases at room temperature but others are liquid or solid?
Otrada [13]

Answer:

The presence of strong intermolecular forces favors a condensed state of matter. liquid or solid), while very weak intermolecular interaction favor the gaseous state.

4 0
2 years ago
Please answer thanks
cupoosta [38]
A) 20Newtons is the answer
7 0
3 years ago
Read 2 more answers
A 37-cm-long wire of linear density 18 g/m vibrating at its second mode, excites the third vibrational mode of a tube of length
lora16 [44]

Answer:

T = 4.42 10⁴ N

Explanation:

this is a problem of standing waves, let's start with the open tube, to calculate the wavelength

        λ = 4L / n                 n = 1, 3, 5, ...    (2n-1)

How the third resonance is excited

       m = 3

       L = 192 cm = 1.92 m

       λ = 4 1.92 / 3

       λ = 2.56 m

As in the resonant processes, the frequency is maintained until you look for the frequency in this tube, with the speed ratio

      v = λ f

      f = v / λ

      f = 343 / 2.56

      f = 133.98 Hz

       

Now he works with the rope, which oscillates in its second mode m = 2 and has a length of L = 37 cm = 0.37 m

The expression for standing waves on a string is

           λ = 2L / n

           λ = 2 0.37 / 2

           λ = 0.37 m

The speed of the wave is

          v = λ f

As we have some resonance processes between the string and the tube the frequency is the same

          v = 0.37 133.98

          v = 49.57 m / s

Let's use the relationship of the speed of the wave with the properties of the string

              v = √ T /μ

              T = v² μ

              T = 49.57²   18

              T = 4.42 10⁴ N

4 0
3 years ago
Read 2 more answers
When at rest, a ruler has a length of 12.0 inches. How fast (in m/s) must the ruler fly past you in order for it to shorten to 6
PIT_PIT [208]

Answer:

2.598×10^8 m/sec

Explanation:

The length of the contraction is given by l=l_0\sqrt{1-\frac{v^2}{c^2}} here l_0 is length of the ruler at rest which is given as 12 inches

l is the length of the ruler in moving condition which is given as 6 inches c is the speed of the light and v is the velocity of the ruler.

l=l_0\sqrt{1-\frac{v^2}{c^2}}

\frac{l}{l_0}=\sqrt{1-\frac{v^2}{c^2}}

1-(\frac{l}{l_0})^2=\frac{v^2}{c^2}

1-(\frac{6}{12})^2=\frac{v^2}{c^2}

0.866=\frac{v}{c}

v=0.866\times 3\times 10^8=2.598\times 10^8 m/sec

3 0
3 years ago
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