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Readme [11.4K]

I’m pretty sure Scale drawings is the correct answer!

6 0

3 years ago

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Write five next terms:0;1;1;2;3;5;8;13

Iteru [2.4K]

Answer:

it's a(n)=a(n-1)+a(n-2)

this is also known as Fibonacci sequence

0

1

2

3

5

8

13

21

34

55

89

144

233

377

610

7 0

2 years ago

Find the difference of 6 1/3 3 3/4

earnstyle [38]

It's 2 7/12

Hope this helped!

6 0

3 years ago

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In a large data set the 40th percentile is 125 and the 82nd percentile is 158. Approximately what percentage of observations lie

liq [111]

Answer:

42% of observations lie between 125 and 158.

Step-by-step explanation:

Interpretation of a percentile

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

Two values have a percentile, how many are between then?

In this example, y is larger than x.

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

When a value Z is said to be in the yth percentile of a set, y% of the values in the set are lower than V and (100-y)% of the values in the set are higher than V.

Also, (y-x)% of the values are between V and Z.

In this problem, we have that:

125 is the 40th percentile

158 is the 82nd percentile

Approximately what percentage of observations lie between 125 and 158

82 - 40 = 42% of observations lie between 125 and 158.

3 0

3 years ago

A formula for the relationship between weight and blood pressure in children is given by the formula below where P(x) is measure

photoshop1234 [79]

Answer:

The rate of change of blood pressure at the 50-pound weight level is 0.26

The rate of change of blood pressure at the 80-pound weight level is 0.16

Step-by-step explanation:

We have, P(x) = 12.9(9 + ln x)

We need to compute the rate of change of blood pressure P(x) so, we will differentiate the function P(x) with respect to x.

P(x) = 12.9(9 + ln x)

P(x) = 116.1 + 12.9ln x

Differentiating with repect to x:

$\frac{d(P(x))}{dx}$ = 0 + 12.9 ( $\frac{1}{x}$ )

$\frac{d(P(x))}{dx}$ = 12.9 ( $\frac{1}{x}$ )

The differential of ln x is $\frac{1}{x}$ and the differential of constant terms is 0.

The rate of change of blood pressure at the 50-pound weight level can be calculate by substituting 50 in place of x, so

$\frac{d(P(x))}{dx}$ = 12.9 ( $\frac{1}{x}$ )

= 12.9 * (1/50)

= 0.258

$\frac{d(P(x))}{dx}$ = 0.26

Similarly, The rate of change of blood pressure at the 80-pound weight level can be calculate by substituting 80 in place of x, so

$\frac{d(P(x))}{dx}$ = 12.9 ( $\frac{1}{x}$ )

= 12.9 * (1/80)

= 0.16125

$\frac{d(P(x))}{dx}$ = 0.16

6 0

3 years ago

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