Question

Thirty-two cyclists make a seven-day trip. Each cyclist requires 8.33 kilograms of food for the entire trip. If each cyclist wants to eat an equal amount of food each day, how many kilograms of food will the group be carrying at the end of Day 5?

Answer 1

Answer:

76.16 kilograms of food

Step-by-step explanation:

Number of cyclist = 32

Food per cyclist = 8.33 kilograms

Days of the trip = 7 days

Food per cyclist per day = 8.33 kg / 7

= 1.19kg food per day for each cyclist

how many kilograms of food will the group be carrying at the end of Day 5?

5 days out of 7 days = 2 days

Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days

= 2 × 1.19

= 2.38 kilograms of food for two days

32 cyclist for 2 days = 32 × 2.38 kg of food

= 76.16 kilograms of food

The group will be carrying 76.16 kilograms of food at the end of Day 5