Answer:
- perimter of original rectangle = <u>17. 6 mm</u>
- side length of the enlarged rectangle = <u>23. 22 mm</u>
- perimeter of the enlarged rectangle = <u>95. 04 mm</u>
Step-by-step explanation:
<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>
- Length of original rectangle = 4.5 mm
- Width of original rectangle = 4.3 mm
<em>perimeter = 2 × ( length + width)</em>
= 2 × ( 4.5 + 4.3)
= 2 × 8.8
= 17. 6 mm
<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>
- Width of original rectangle = 4. 5 mm
- Width of enlarged rectangle = 24.3 mm
Enlargement factor = 24.3 / 4.5
= 5.4
- Length of original rectangle = 4.5 mm
- Enlargement factor = 5.4
Side length of enlarged rectangle
= original length × Enlargement factor
= 4.3 × 5.4
= 23. 22 mm
<u>PERIMTER OF ENLARGED RECTANGLE</u>
= 2 × ( enlarged ength + enlarged breadth)
= 2 × (23. 22 + 24. 3 )
= 95. 04 mm
-12 + 9 - (-3) - 11
Remember PEMDAS: This is the order of operation.
P-Paragrahp
E-Exponent
M-Multiply
D-Divide
A-Add
S-Subtract
1st step: PEM
-(-3) is actually -1 * -3 = + 3
-12 + 9 + 3 - 11
2nd step: D is not possible, so we do A.
9 + 3 = 12
3rd Step: Subtract
12 - 12 - 11 = 0 - 11 = -11 CHOICE B.
The fraction indicating the number of students who are not wearing either blue or white shirt is:
1- 1/6- 2/3= 1/6.
36 students* (1/6)= 6 students.
There are 6 students who are not wearing either a blue or a white shirt.
Hope this helps~
