Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
Answer:
Imarie uses a microscope to study different prokaryotic and eukaryotic organisms. Which of the following statements describes how the prokaryotic cells appear compared to the eukaryotic cells? The prokaryotic cells are much smaller than the eukaryotic cells.
Answer:
Si existe variación en el acervo genético de la población, esto permite que la selección natural actúe sobre los rasgos de la población que permiten la adaptación al ambiente cambiante. Cuanta más diversidad hay en una población, mayor es la probabilidad de que la población pueda adaptarse a los nuevos cambios.
Explanation:
Answer:
hemotrophs are organisms that obtain energy by the oxidation of electron donors in their environment. Chemoautotrophs use inorganic energy sources to synthesize organic compounds from carbon dioxide. Chemoheterotrophs are unable to utilize carbon dioxide to form their own organic compounds.
Explanation:
