Answer: 200 seeds will be yellow.
Explanation: In this crossing, one parent will produce half of its gametes carrying allele Y and the other half carrying allele y. The other parent will have gametes with allele Y. After fecundation, the offspring could phenotype YY or phenotype Yy. 
In genetics, Y is related to the dominant allele and y to the recessive one. In this case, having the Y dominant allele determine the color yellow. Therefore, as all of the offspring has the dominant allele Y for yellow, all of the seeds will be yellow, i.e., <u>200 seeds will be yellow</u>.
 
        
             
        
        
        
Answer:
3/16
Explanation:
Given,
Black coat color is dominant over brown coat color.
Long mane is dominant over short mane.
BBLL X bbll = 
F1: BbLl = Entire progeny has black color and long mane
BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,
BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1
3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane. 
 
        
             
        
        
        
Answer:
Its B I think (I'm not 100% sure)
Explanation:
 
        
             
        
        
        
Mirror neurons are said to be the factors behind social imitation. Neurons are the main cell of the nervous system which is responsible for communication of organs and control of many bodily functions. In an evolutionary standpoint, mirror neurons are an advantage because humans are able to replicate and imitate skills, behaviors and practices which they find beneficial and advantageous in the wild. Among their social peers, mirror neurons help these individuals practice social inclusion through culture, values and practices for increased group cohesion and cooperation. 
        
             
        
        
        
Mitral valve prolapse severe enough to cause regurgitation may directly cause INCREASE pressure in the LEFT atrium. Mitral valve prolapse is a medical condition in which the the two valve flaps of the mitral valve do not close properly, bulging upward into the left atrium. The condition may be mild or severe. Heart surgery may be required in case of the severe one.