I'll do a similar problem, and I challenge you to do this using similar techniques!
If John works for 15$ a hour with his friends rather than working for 20$ an hour for 50 hours a month, what's the monthly opportunity cost?
John would make 20*50=1000 dollars a month at the second option as he makes 20$ an hour 50 times. Next, if he works with his friends, he makes 15*50=750 dollars as he works 50 hours for 15 dollars an hour, or adds 15 50 times.
His opportunity cost would be <highest money>-<lowest money>=1000-750=250 dollars a month. Good luck on this question, and feel free to ask further questions!
(x2 +1) (x2-4) (mark as brainiest)
Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
This is your answer
<span>-12 - 5 (first one)
hope that helps
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Based on this sample, 100 toys will not meet standards.
There is 1 value that is 75 or lower in this simulation. This makes the experimental probability 1/10. 1/10(1000) = 100 toys for the month.